Python递归目录并统计指定后缀文件个数

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递归某目录下所有文件,以及打印出这些文件的上一级目录,文件名和后缀名等.

import os

def recur_files(path):
    pcd_lst = []
    label_lst = []
    parents = os.listdir(path)
    for parent in parents:
        child = os.path.join(path,parent)
        if os.path.isdir(child):
            recur_files(child)
        else:
            print(os.path.dirname(child))#parent folder
            basename, ext = os.path.splitext(os.path.basename(child))
            print(basename)#filename
            print(ext)#extention,include'.'

加上统计某一后缀文件个数功能:

import os

count = 0

def recur_files(path):
    global count
    parents = os.listdir(path)
    for parent in parents:
        child = os.path.join(path,parent)
        if os.path.isdir(child):
            recur_files(child)
        else:
            basename, ext = os.path.splitext(os.path.basename(child))

            if ext == '.pcd':
                count += 1

    return count
import os


pcd_lst = []
label_lst = []
def recur_files(path):
    for root, _, files in os.walk(path):
        for file in files:
            if file.endswith(".pcd"):
                pcd_lst.append(os.path.join(root, file))


if __name__ == '__main__':
    my_dir = os.getcwd()
    recur_files(my_dir)
    label_lst = [p.replace('pcds', 'labels') for p in pcd_lst]
    label_lst = [l.replace('.pcd', '.json') for l in label_lst]
    assert(len(pcd_lst) == len(label_lst))
    length = len(pcd_lst)
    with open(os.path.join('train_list.txt'),'wb') as fin:
        for i in range(length):
            fin.write(pcd_lst[i] + " " + label_lst[i]  + "\n")

参考:震惊!Python竟然是这样的修改全局变量

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转载自blog.csdn.net/xiangxianghehe/article/details/81386420