获得两个日期中间间隔的天数

方法一:

def isLeapYear(year):
    ##
    # Your code here. Return True or False
    # Pseudo code for this algorithm is found at
    # http://en.wikipedia.org/wiki/Leap_year#Algorithm
    ##
    return year%400==0 or year%4==0 and year%100!=0

daysOfMonths = [ 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]

def daysAdd(y1, m1, d1):
	if isLeapYear(y1):
		daysOfMonths[1] = 29
	else:
		daysOfMonths[1] = 28
	d1 = d1+1
	if d1>daysOfMonths[m1-1]:
		d1 = 1
		y1,m1 = mounthAdd(y1,m1)
	return y1,m1,d1

def mounthAdd(y1, m1):
	m1 = m1+1
	if m1>12:
		m1 = 1
		y1 = y1+1
	return y1,m1

def daysBetweenDates(y1, m1, d1, y2, m2, d2):
	day = 0
	while  True:
		y1,m1,d1 = daysAdd(y1,m1,d1)
		day+=1
		if y1==y2 and m1==m2 and d1==d2:
			break
	return day


# print isLeapYear(2100)
print daysBetweenDates(2017,12,26,2017,12,27)

方法二:

def leap(year):
    if year%400==0:
        return True
    elif year%100==0:
        return False
    elif year%4==0:
        return True
    else:
        return False


def dayofmonth(month,year):
    days=[0,31,28,31,30,31,30,31,31,30,31,30,31]
    if month!=2:
        return days[month]
    return days[2]+int(leap(year))
    


def nextDay(year, month, day):
    """Simple version: assume every month has 30 days"""
    if day < dayofmonth(month,year):
        return year, month, day + 1
    else:
        if month == 12:
            return year + 1, 1, 1
        else:
            return year, month + 1, 1
        
def dateIsBefore(year1, month1, day1, year2, month2, day2):
    """Returns True if year1-month1-day1 is before year2-month2-day2. Otherwise, returns False."""
    if year1 < year2:
        return True
    if year1 == year2:
        if month1 < month2:
            return True
        if month1 == month2:
            return day1 < day2
    return False        


def daysBetweenDates(year1, month1, day1, year2, month2, day2):
    """Returns the number of days between year1/month1/day1
       and year2/month2/day2. Assumes inputs are valid dates
       in Gregorian calendar."""
    # program defensively! Add an assertion if the input is not valid!
    assert not dateIsBefore(year2, month2, day2, year1, month1, day1)
    days = 0
    while dateIsBefore(year1, month1, day1, year2, month2, day2):
        year1, month1, day1 = nextDay(year1, month1, day1)
        days += 1
    return days


def test():
    test_cases = [((2012,9,30,2012,10,30),30), 
                  ((2012,1,1,2013,1,1),366),
                  ((2012,9,1,2012,9,4),3),
                  ((2013,1,1,1999,12,31), "AssertionError")]
    
    for (args, answer) in test_cases:
        try:
            result = daysBetweenDates(*args)
            if result != answer:
                print "Test with data:", args, "failed"
            else:
                print "Test case passed!"
        except AssertionError:
            if answer == "AssertionError":
                print "Nice job! Test case {0} correctly raises AssertionError!\n".format(args)
            else:
                print "Check your work! Test case {0} should not raise AssertionError!\n".format(args) 


test()