oralce逗号分割变多行

方法一

select  a.*  , 

REGEXP_SUBSTR(a.rolecode ,'[^,]+',1,l) AS rolecode 

from p_user a,(SELECT LEVEL l FROM DUAL CONNECT BY LEVEL<=100) b

WHERE l <=LENGTH(a.rolecode) - LENGTH(REPLACE(rolecode,','))+1

使用函数REGEXP_SUBSTR拆分字符串:

5个参数

第一个是输入的字符串

第二个是正则表达式

第三个是标识从第几个字符开始正则表达式匹配。(默认为1)

第四个是标识第几个匹配组。(默认为1)

第五个是是取值范围:

i:大小写不敏感;

c:大小写敏感; 

n:点号 . 不匹配换行符号;

m:多行模式;

x:扩展模式,忽略正则表达式中的空白字符。

SELECT a.*,REGEXP_SUBSTR(servicereqid ,'[^;]+',1,l) AS servicereq

  FROM sum_portal_satisfaction a,(SELECT LEVEL l FROM DUAL CONNECT BY LEVEL<=100) b

WHERE l <=LENGTH(servicereqid) - LENGTH(REPLACE(servicereqid,';'))+1

ORDER BY 1,2;

 

----SELECT LEVEL l FROM DUAL CONNECT BY LEVEL<=100; 生成1到100的数据行。

----l <=LENGTH(servicereqid) - LENGTH(REPLACE(servicereqid,';'))+1,注意此处是‘L’并非‘1’,上面的REGEXP_SUBSTR的第四个参数也一样。

 

---下面为拆分字符串,再进行的行转列

create or replace view v_sum_portal_satisfaction_sr as

select 

survey_type,

survey_time,

center_code,

center_name,

city_id,

city_name,

REGEXP_SUBSTR(servicereqid ,'[^;]+',1,l) AS servicereqid,

REGEXP_SUBSTR(servicereqname ,'[^;]+',1,l) AS servicereqname,

sum(decode(survey_value,0, sur_times,null)) giveup_times,--调查值 -1:未处理 0:用户放弃 1:很满意 2.满意 3.对csr不满意 4.对其它不满意

sum(decode(survey_value,1, sur_times,null))vsatis_times,

sum(decode(survey_value,2, sur_times,null))satis_times,

sum(decode(survey_value,3, sur_times,null))ncsr_times,

sum(decode(survey_value,4, sur_times,null))nelse_times,

sum(sur_times) sur_times

  FROM sum_portal_satisfaction a,(SELECT LEVEL l FROM DUAL CONNECT BY LEVEL<=100) b

WHERE l <=LENGTH(servicereqid) - LENGTH(REPLACE(servicereqid,';'))+1

group by

subslevelid,

center_code,

center_name,

city_id,

city_name,

survey_type,

survey_time,

servicereqid,

servicereqname,l

 

方法二:

create table  testTable (

       id  nvarchar2(200) primary key not null ,

       content  nvarchar2(200) not null 

)

insert into  testTable values ('4','馆内idx_10馆外idx_11总体idx_12');

select *  from table ( CAST (fn_split(('馆内idx_1$馆外idx_2$总体idx_3$') ,'$') as ty_str_split  )  )

select * from testtable b left join  table (fn_split((content), '$')   ) a   on 1=1;

--实现split函数

CREATE OR REPLACE TYPE ty_str_split IS TABLE OF VARCHAR2 (4000);

CREATE OR REPLACE FUNCTION fn_split (p_str IN VARCHAR2, p_delimiter IN VARCHAR2)

    RETURN ty_str_split

IS

    j INT := 0;

    i INT := 1;

    len INT := 0;

    len1 INT := 0;

    str VARCHAR2 (4000);

    str_split ty_str_split := ty_str_split ();

BEGIN

    len := LENGTH (p_str);

    len1 := LENGTH (p_delimiter);

 

    WHILE j < len

    LOOP

        j := INSTR (p_str, p_delimiter, i);

 

        IF j = 0

        THEN

            j := len;

            str := SUBSTR (p_str, i);

            str_split.EXTEND;

            str_split (str_split.COUNT) := str;

 

            IF i >= len

            THEN

                EXIT;

            END IF;

        ELSE

            str := SUBSTR (p_str, i, j - i);

            i := j + len1;

            str_split.EXTEND;

            str_split (str_split.COUNT) := str;

        END IF;

    END LOOP;

 

    RETURN str_split;

END fn_split;

 

DECLARE

    CURSOR c

    IS

select *  from table ( CAST (fn_split(('馆内idx_1$馆外idx_2$总体idx_3$') ,'$') as ty_str_split  )  );

 

    r c%ROWTYPE;

BEGIN

    OPEN c;

 

    LOOP

        FETCH c INTO r;

        EXIT WHEN c%NOTFOUND;

        DBMS_OUTPUT.put_line (r.column_value);

    END LOOP;

 

    CLOSE c;

END;

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转载自blog.csdn.net/mss359681091/article/details/79753593
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