LeetCode之Find and Replace Pattern（Kotlin）

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问题：
You have a list of words and a pattern, and you want to know which words in words matches the pattern.
A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the desired word.
(Recall that a permutation of letters is a bijection from letters to letters: every letter maps to another letter, and no two letters map to the same letter.)
Return a list of the words in words that match the given pattern.
You may return the answer in any order.

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方法：
对于每个字符串和映射字符串来说，如果映射关系中包含a->b，则map的key中包含a，则value中必包含b，反之，如果map的value中包含b，则key中必不包含a。根据如上规则，遍历整个字符串组则可以得到符合映射关系的字符串，算法复杂度为O(n)。

具体实现：

class FindAndReplacePattern {
    fun findAndReplacePattern(words: Array<String>, pattern: String): List<String> {
        val result = mutableListOf<String>()
        loop@ for (word in words) {
            val map = mutableMapOf<Char, Char>()
            for (i in word.indices) {
                if (map.containsKey(word[i])) {
                    val char = map[word[i]]
                    if (char != pattern[i]) {
                        continue@loop
                    }
                } else {
                    if (map.containsValue(pattern[i])) {
                        continue@loop
                    }
                }
                map.put(word[i], pattern[i])
            }
            result.add(word)
        }
        return result
    }
}

fun main(args: Array<String>) {
    val words = arrayOf("abc","deq","mee","aqq","dkd","ccc")
    val pattern = "abb"
    val findAndReplacePattern = FindAndReplacePattern()
    CommonUtils.printArray(findAndReplacePattern.findAndReplacePattern(words, pattern).toTypedArray())
}

有问题随时沟通

具体代码实现可以参考Github