Mysql常用SQL语句集锦

基础篇

//查询时间，友好提示
$sql = "select date_format(create_time, '%Y-%m-%d') as day from table_name";
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//int 时间戳类型
$sql = "select from_unixtime(create_time, '%Y-%m-%d') as day from table_name";
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//一个sql返回多个总数
$sql = "select count(*) all, " ;
$sql .= " count(case when status = 1 then status end) status_1_num, ";
$sql .= " count(case when status = 2 then status end) status_2_num ";
$sql .= " from table_name";
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//Update Join / Delete Join
$sql = "update table_name_1 ";
$sql .= " inner join table_name_2 on table_name_1.id = table_name_2.uid ";
$sql .= " inner join table_name_3 on table_name_3.id = table_name_1.tid ";
$sql .= " set *** = *** ";
$sql .= " where *** ";
//delete join 同上。
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//替换某字段的内容的语句
$sql = "update table_name set content = REPLACE(content, 'aaa', 'bbb') ";
$sql .= " where (content like '%aaa%')";
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//获取表中某字段包含某字符串的数据
$sql = "SELECT * FROM `表名` WHERE LOCATE('关键字', 字段名) ";
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//获取字段中的前4位
$sql = "SELECT SUBSTRING(字段名,1,4) FROM 表名 ";
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//查找表中多余的重复记录
//单个字段
$sql = "select * from 表名 where 字段名 in ";
$sql .= "(select 字段名 from 表名 group by 字段名 having count(字段名) > 1 )";
//多个字段
$sql = "select * from 表名 别名 where (别名.字段1,别名.字段2) in ";
$sql .= "(select 字段1,字段2 from 表名 group by 字段1,字段2 having count(*) > 1 )";
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//删除表中多余的重复记录(留id最小)
//单个字段
$sql = "delete from 表名 where 字段名 in ";
$sql .= "(select 字段名 from 表名 group by 字段名 having count(字段名) > 1) ";
$sql .= "and 主键ID not in ";
$sql .= "(select min(主键ID) from 表名 group by 字段名 having count(字段名 )>1) ";
//多个字段
$sql = "delete from 表名 别名 where (别名.字段1,别名.字段2) in ";
$sql .= "(select 字段1,字段2 from 表名 group by 字段1,字段2 having count(*) > 1) ";
$sql .= "and 主键ID not in ";
$sql .= "(select min(主键ID) from 表名 group by 字段1,字段2 having count(*)>1) ";
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业务篇

• 连续范围问题

//创建测试表
CREATE TABLE `test_number` (
 `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
 `number` int(11) unsigned NOT NULL DEFAULT '0' COMMENT '数字',
 PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8
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//创建测试数据
insert into test_number values(1,1);
insert into test_number values(2,2);
insert into test_number values(3,3);
insert into test_number values(4,5);
insert into test_number values(5,7);
insert into test_number values(6,8);
insert into test_number values(7,10);
insert into test_number values(8,11);
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实验目标：求数字的连续范围。

根据上面的数据，应该得到的范围。

1-3
5-5
7-8
10-11
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//执行Sql
select min(number) start_range,max(number) end_range
from
(
 select number,rn,number-rn diff from
 (
 select number,@number:=@number+1 rn from test_number,(select @number:=0) as number
 ) b
) c group by diff;
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数字的连续范围

• 签到问题

//创建参考表(模拟数据需要用到)
CREATE TABLE `test_nums` (
 `id` int(11) unsigned NOT NULL AUTO_INCREMENT,
 PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COMMENT='参考表';
//模拟数据，插入 1-10000 连续数据.
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//创建测试表
CREATE TABLE `test_sign_history` (
 `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
 `uid` int(11) unsigned NOT NULL DEFAULT '0' COMMENT '用户ID',
 `create_time` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP COMMENT '签到时间',
 PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COMMENT='签到历史表';
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//创建测试数据
insert into test_sign_history(uid,create_time)
select ceil(rand()*10000),str_to_date('2016-12-11','%Y-%m-%d')+interval ceil(rand()*10000) minute
from test_nums where id<31;
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//统计每天的每小时用户签到情况
select
 h,
 sum(case when create_time='2016-12-11' then c else 0 end) 11Sign,
 sum(case when create_time='2016-12-12' then c else 0 end) 12Sign,
 sum(case when create_time='2016-12-13' then c else 0 end) 13Sign,
 sum(case when create_time='2016-12-14' then c else 0 end) 14Sign,
 sum(case when create_time='2016-12-15' then c else 0 end) 15Sign,
 sum(case when create_time='2016-12-16' then c else 0 end) 16Sign,
 sum(case when create_time='2016-12-17' then c else 0 end) 17Sign
from
(
 select
 date_format(create_time,'%Y-%m-%d') create_time,
 hour(create_time) h,
 count(*) c
 from test_sign_history
 group by
 date_format(create_time,'%Y-%m-%d'),
 hour(create_time)
) a
group by h with rollup;
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统计每天的每小时用户签到情况

//统计每天的每小时用户签到情况(当某个小时没有数据时，显示0)
select
 h ,
 sum(case when create_time='2016-12-11' then c else 0 end) 11Sign,
 sum(case when create_time='2016-12-12' then c else 0 end) 12Sign,
 sum(case when create_time='2016-12-13' then c else 0 end) 13Sign,
 sum(case when create_time='2016-12-14' then c else 0 end) 14Sign,
 sum(case when create_time='2016-12-15' then c else 0 end) 15Sign,
 sum(case when create_time='2016-12-16' then c else 0 end) 16Sign,
 sum(case when create_time='2016-12-17' then c else 0 end) 17Sign
from
(
 select b.h h,c.create_time,c.c from
 (
 select id-1 h from test_nums where id<=24
 ) b
 left join
 (
 select
 date_format(create_time,'%Y-%m-%d') create_time,
 hour(create_time) h,
 count(*) c
 from test_sign_history
 group by
 date_format(create_time,'%Y-%m-%d'),
 hour(create_time)
 ) c on (b.h=c.h)
) a
group by h with rollup;
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统计每天的每小时用户签到情况(当某个小时没有数据时，显示0)

//统计每天的用户签到数据和每天的增量数据
select
 type,
 sum(case when create_time='2016-12-11' then c else 0 end) 11Sign,
 sum(case when create_time='2016-12-12' then c else 0 end) 12Sign,
 sum(case when create_time='2016-12-13' then c else 0 end) 13Sign,
 sum(case when create_time='2016-12-14' then c else 0 end) 14Sign,
 sum(case when create_time='2016-12-15' then c else 0 end) 15Sign,
 sum(case when create_time='2016-12-16' then c else 0 end) 16Sign,
 sum(case when create_time='2016-12-17' then c else 0 end) 17Sign
from
(
 select b.create_time,ifnull(b.c-c.c,0) c,'Increment' type from
 (
 select
 date_format(create_time,'%Y-%m-%d') create_time,
 count(*) c
 from test_sign_history
 group by
 date_format(create_time,'%Y-%m-%d')
 ) b
 left join
 (
 select
 date_format(create_time,'%Y-%m-%d') create_time,
 count(*) c
 from test_sign_history
 group by
 date_format(create_time,'%Y-%m-%d')
 ) c on(b.create_time=c.create_time+ interval 1 day)
 union all
 select
 date_format(create_time,'%Y-%m-%d') create_time,
 count(*) c,
 'Current'
 from test_sign_history
 group by
 date_format(create_time,'%Y-%m-%d')
) a
group by type
order by case when type='Current' then 1 else 0 end desc;
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统计每天的用户签到数据和每天的增量数据

//模拟不同的用户签到了不同的天数
insert into test_sign_history(uid,create_time)
select uid,create_time + interval ceil(rand()*10) day from test_sign_history,test_nums
where test_nums.id <10 order by rand() limit 150;
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//统计签到天数相同的用户数量
select
 sum(case when day=1 then cn else 0 end) 1Day,
 sum(case when day=2 then cn else 0 end) 2Day,
 sum(case when day=3 then cn else 0 end) 3Day,
 sum(case when day=4 then cn else 0 end) 4Day,
 sum(case when day=5 then cn else 0 end) 5Day,
 sum(case when day=6 then cn else 0 end) 6Day,
 sum(case when day=7 then cn else 0 end) 7Day,
 sum(case when day=8 then cn else 0 end) 8Day,
 sum(case when day=9 then cn else 0 end) 9Day,
 sum(case when day=10 then cn else 0 end) 10Day
from
(
 select c day,count(*) cn
 from
 (
 select uid,count(*) c from test_sign_history group by uid
 ) a
 group by c
) b;
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统计签到天数相同的用户数量

//统计每个用户的连续签到时间
select * from (
 select d.*,
 @ggid := @cggid,
 @cggid := d.uid,
 if(@ggid = @cggid, @grank := @grank + 1, @grank := 1) grank
 from
 (
 select uid,min(c.create_time) begin_date ,max(c.create_time) end_date,count(*) count from
 (
 select
 b.*,
 @gid := @cgid,
 @cgid := b.uid,
 if(@gid = @cgid, @rank := @rank + 1, @rank := 1) rank,
 b.diff-@rank flag from (
 select
 distinct
 uid,
 date_format(create_time,'%Y-%m-%d') create_time,
 datediff(create_time,now()) diff
 from test_sign_history order by uid,create_time
 ) b, (SELECT @gid := 1, @cgid := 1, @rank := 1) as a
 ) c group by uid,flag
 order by uid,count(*) desc
 ) d,(SELECT @ggid := 1, @cggid := 1, @grank := 1) as e
)f
where grank=1;
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统计每个用户的连续签到时间

如果大家需要下载上述的相关数据表，进行测试。

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