购物车作业

li=[{'name':'苹果','price':10,},
    {'name':'香蕉','price':20,},
    {'name':'西瓜','price':30,}]
print('欢迎进入蓝色水果店')
money=input('请输入你所拥有的钱:')
shopping_car= {}
if money.isdigit() and int( money ) > 0:
    while 1:
        for i, k in enumerate(li):
            print('序号{},商品名称{}.商品价格{}'.format(i, k['name'], k['price']))
        choose = input('请输入你想要购买的商品序号')
        if choose.isdigit() and int(choose) < len(li):
            num = input('请输入你需要购买的商品数量')
            if num.isdigit():
                if li[int(choose)]['price'] * int(num) <=int(money):
                    money = int(money) - li[int(choose)]['price'] * int(num)
                    if li[int(choose)]['name'] in shopping_car:
                        shopping_car[li[int(choose)]['name']]=shopping_car[li[int(choose)]['name']]+int( num )
                    else:
                        shopping_car[li[int(choose)]['name']]=int(num)
                        print('你的购物车中商品有{},剩余余额为{}'.format(shopping_car,money))
                else:
                    print('对不起,你带的钱不够,滚好吗')
                    break
            else:
                print('让你输入商品数量,还要我安排尼玛?')
        else:
            print('请你输入正确的序号')

PS:一、li=[{},{}],列表里面包含字典

  二、isdigit()函数判断数字类型

  三、li[int(choose)]['price']

  四、for i, k in enumerate(li):

      print('序号{},商品名称{}.商品价格{}'.format(i, k['name'], k['price']))

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转载自www.cnblogs.com/qq946487854/p/9812935.html
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