python+数据过滤、清理、转换

版权声明:本文为博主原创文章,未经博主允许不得转载。 https://blog.csdn.net/LY_ysys629/article/details/73873601

本篇博客主要内容

1)移除重复数据(duplicated)

2)利用函数或映射进行数据转换(map)

3)替换值(replace)

4)重命名轴索引

5)检测和过滤异常值(逻辑索引)

6)随机采样或选出随机子集

7)计算哑变量(get_dummies)

1)移除重复数据

检查某列数据是否重复可用.is_unique

检查某行数据是否重复可用.duplicated

import pandas as pd
import numpy as np

data = pd.DataFrame({'k1':['one'] * 3 + ['two'] * 4,'k2':[1,1,2,3,3,4,4]})
data
k1 k2
0 one 1
1 one 1
2 one 2
3 two 3
4 two 3
5 two 4
6 two 4

检查列以及行中重复数据

data.index.is_unique#检查列
    True
data.k1.is_unique#检查列
    False
data['k2'].is_unique#检查列
    False
data.is_unique
---------------------------------------------------------------------------

AttributeError                            Traceback (most recent call last)

<ipython-input-12-3c5fb82b7563> in <module>()
----> 1 data.is_unique


C:\Program Files\anaconda\lib\site-packages\pandas\core\generic.pyc in __getattr__(self, name)
   2670             if name in self._info_axis:
   2671                 return self[name]
-> 2672             return object.__getattribute__(self, name)
   2673 
   2674     def __setattr__(self, name, value):


AttributeError: 'DataFrame' object has no attribute 'is_unique'
data.duplicated()#检查行
    0    False
    1     True
    2    False
    3    False
    4     True
    5    False
    6     True
    dtype: bool

移除重复行

data.drop_duplicates()
k1 k2
0 one 1
2 one 2
3 two 3
5 two 4
set(data.k1)#保留唯一的列属性值
    {'one', 'two'}

移除重复值小结

1) drop_duplicates、duolicated函数只能用于DataFrame

2) is_unique不能用于DataFrame

2)利用函数或映射进行数据转换

data1 = pd.DataFrame({'food':['bacon','pork','bacon','Pastrami',\
                              'beef','Bacon','pastrami','ham','lox'],\
                      'ounces':[4,3,12,6,7.5,8,3,5,6]})
data1
food ounces
0 bacon 4.0
1 pork 3.0
2 bacon 12.0
3 Pastrami 6.0
4 beef 7.5
5 Bacon 8.0
6 pastrami 3.0
7 ham 5.0
8 lox 6.0

添加一列表示肉类来源的动物类型

#step1:构建肉类到动物的映射
meat_to_animal = {'bacon':'pig','pork':'pig','pastrami':'cow','beef':'cow','ham':'pig',\
                 'lox':'salmon'}

Series的map方法可以接受一个函数或含有映射关系的字典型对象,字符的大小写要一致

#step2:映射
data1['animal'] = data1['food'].map(str.lower).map(meat_to_animal)
data1
food ounces animal
0 bacon 4.0 pig
1 pork 3.0 pig
2 bacon 12.0 pig
3 Pastrami 6.0 cow
4 beef 7.5 cow
5 Bacon 8.0 pig
6 pastrami 3.0 cow
7 ham 5.0 pig
8 lox 6.0 salmon
#step2的另一种实现方法

data1['food'].map(lambda x:meat_to_animal[x.lower()])
    0       pig
    1       pig
    2       pig
    3       cow
    4       cow
    5       pig
    6       cow
    7       pig
    8    salmon
    Name: food, dtype: object
data1
food ounces animal
0 bacon 4.0 pig
1 pork 3.0 pig
2 bacon 12.0 pig
3 Pastrami 6.0 cow
4 beef 7.5 cow
5 Bacon 8.0 pig
6 pastrami 3.0 cow
7 ham 5.0 pig
8 lox 6.0 salmon

map是一种实现元素级转换记忆其他数据清理工作的便捷方式

map会改变原始数据集

3)替换值

替换缺失值的方法:

1)fillna

2)含有重复索引的合并combine_first

3)replace

data2 = pd.Series([1.,-999,2,-999,-1000,3.])
data2
    0       1.0
    1    -999.0
    2       2.0
    3    -999.0
    4   -1000.0
    5       3.0
    dtype: float64

-999可能是一个表示缺失数据的标记值,要将其替换为pandas能够理解的NA值,可以利用replace

data2.replace(-999,np.nan)
    0       1.0
    1       NaN
    2       2.0
    3       NaN
    4   -1000.0
    5       3.0
    dtype: float64
data2
    0       1.0
    1    -999.0
    2       2.0
    3    -999.0
    4   -1000.0
    5       3.0
    dtype: float64

replace不改变原数据集

一次性替换多个值

data2.replace([-999,-1000],np.nan)#一次传入一个列表即可
    0    1.0
    1    NaN
    2    2.0
    3    NaN
    4    NaN
    5    3.0
    dtype: float64
data2.replace([-999,-1000],[np.nan,0])
    0    1.0
    1    NaN
    2    2.0
    3    NaN
    4    0.0
    5    3.0
    dtype: float64
data2.replace({-999:np.nan,-1000:0})
    0    1.0
    1    NaN
    2    2.0
    3    NaN
    4    0.0
    5    3.0
    dtype: float64

4)重命名轴索引

跟Series中的值一样,轴标签也可以通过函数或映射进行转换,从而得到一个新对象,轴还可以被就地修改,而无需新建一个数据结构

data3 = pd.DataFrame(np.arange(12).reshape(3,4),index = ['a','b','c'],columns = ['one','two','three','four'])
data3
one two three four
a 0 1 2 3
b 4 5 6 7
c 8 9 10 11
data3.index.map(str.upper)
    array(['A', 'B', 'C'], dtype=object)
data3
one two three four
a 0 1 2 3
b 4 5 6 7
c 8 9 10 11
data3.index = data3.index.map(str.upper)#修改了
data3
one two three four
A 0 1 2 3
B 4 5 6 7
C 8 9 10 11

还可以通过rename结合字典型对象实现对部分轴标签的更新

data3.rename(index = {'A':'aaa'},columns = {'three':'liu'})

one two liu four
aaa 0 1 2 3
B 4 5 6 7
C 8 9 10 11
data3#不改变原数据
one two three four
A 0 1 2 3
B 4 5 6 7
C 8 9 10 11
data3 = data3.rename(index = {'A':'aaa'},columns = {'three':'liu'})
data3
one two liu four
aaa 0 1 2 3
B 4 5 6 7
C 8 9 10 11

5)检测和过滤异常值

这里的异常值的阈值已知,因此,异常值的过滤或变换运算很大程度上其实就是逻辑数组运算。

data4 = pd.DataFrame(np.random.randn(1000,4))
data4.info()
data4.describe()
0 1 2 3
count 1000.000000 1000.000000 1000.000000 1000.000000
mean 0.023986 -0.014049 0.032299 -0.037661
std 0.994571 1.003522 1.009939 1.017361
min -3.526970 -3.298974 -3.429383 -3.421995
25% -0.632426 -0.685564 -0.665548 -0.756219
50% 0.013326 0.006130 -0.017911 -0.015297
75% 0.633279 0.670261 0.673849 0.665360
max 3.549620 3.142503 3.991028 3.086376

找出某列绝对值大于3的值

data4[3][np.abs(data4[3]) > 3]
    189   -3.421995
    335    3.086376
    590   -3.388477
    778   -3.100379
    Name: 3, dtype: float64

找出全部或含有“超过3或-3的值”的行

(np.abs(data4) > 3).any(1).head()
    0    False
    1    False
    2    False
    3    False
    4    False
    dtype: bool
data4[(np.abs(data4) > 3).any(1)]
0 1 2 3
109 3.549620 -0.943976 -0.058490 0.941503
189 -0.071249 -1.350361 0.385375 -3.421995
291 2.337961 3.142503 -0.208999 -0.485979
335 0.230998 -1.397259 2.734229 3.086376
447 -3.526970 -0.289467 1.099487 1.206039
464 0.011728 -0.398739 3.104470 0.459924
546 0.357944 0.007063 3.991028 0.722481
573 -3.019947 -0.982651 -1.727289 1.484966
590 0.211069 0.344059 0.656351 -3.388477
660 0.930103 3.117643 -1.372034 -1.208730
663 0.362668 -3.298974 -1.033128 0.900985
778 0.094172 0.827937 2.617724 -3.100379
814 -1.450645 -1.131513 -3.429383 -0.828139
853 1.188536 -3.069987 -0.746700 0.745037
899 2.449030 0.429959 3.025705 -1.571179

替换异常值

data4[np.abs(data4) > 3] = np.sign(data) * 3
data4.isnull().sum()#有空值
    0    3
    1    4
    2    4
    3    4
    dtype: int64
data4 = data4.replace(np.nan,0)
data4.isnull().sum()#无空值
    0    0
    1    0
    2    0
    3    0
    dtype: int64
data4.describe()###?????????
0 1 2 3
count 1000.000000 1000.000000 1000.000000 1000.000000
mean 0.026983 -0.013941 0.025608 -0.030836
std 0.977152 0.983421 0.986831 0.996554
min -2.749595 -2.799638 -2.943564 -2.743207
25% -0.630318 -0.682237 -0.663014 -0.739291
50% 0.012445 0.000613 -0.017171 -0.004484
75% 0.631146 0.668023 0.660236 0.659204
max 2.829804 2.915031 2.907655 2.679495

6)排列和随机采样

1)numpy.random.permutation函数

2)np.random.randint生成随机数

df = pd.DataFrame(np.arange(5 *4).reshape(5,4))

sampler = np.random.permutation(5)
df
0 1 2 3
0 0 1 2 3
1 4 5 6 7
2 8 9 10 11
3 12 13 14 15
4 16 17 18 19
sampler
    array([0, 1, 3, 4, 2])
df.ix[sampler]
0 1 2 3
0 0 1 2 3
1 4 5 6 7
3 12 13 14 15
4 16 17 18 19
2 8 9 10 11
df.take(sampler)
0 1 2 3
0 0 1 2 3
1 4 5 6 7
3 12 13 14 15
4 16 17 18 19
2 8 9 10 11

通过np.random.randint得到一组随机整数

sampler1 = np.random.randint(0,len(df),size = 4)
sampler1
    array([2, 2, 3, 0])
df1 = df.take(sampler1)
df1
0 1 2 3
2 8 9 10 11
2 8 9 10 11
3 12 13 14 15
0 0 1 2 3

7)计算指标/哑变量

将分类变量(categorical variable)转换为(哑变量矩阵,dummy matrix)或(指标矩阵,indicator matrix)是常用于统计学习建模或机器学习的转换方式。

即 DataFrame的某一列中含有k个不同的值,则可以派生出一个k列矩阵或DataFrame(其值为1或0)。

pandas中的get_dummies函数可以实现以上功能

df2 = pd.DataFrame({'key':['b','a','b','c','a','b'],'data1':range(6)})

df2
data1 key
0 0 b
1 1 a
2 2 b
3 3 c
4 4 a
5 5 b
pd.get_dummies(df2.key)
a b c
0 0.0 1.0 0.0
1 1.0 0.0 0.0
2 0.0 1.0 0.0
3 0.0 0.0 1.0
4 1.0 0.0 0.0
5 0.0 1.0 0.0
pd.get_dummies(df2['key'],prefix = 'key')
key_a key_b key_c
0 0.0 1.0 0.0
1 1.0 0.0 0.0
2 0.0 1.0 0.0
3 0.0 0.0 1.0
4 1.0 0.0 0.0
5 0.0 1.0 0.0
## get_dummies矩阵和原数据连接

dummies = pd.get_dummies(df2['key'],prefix = 'key')
pd.concat([df2['data1'],dummies],axis = 1)
data1 key_a key_b key_c
0 0 0.0 1.0 0.0
1 1 1.0 0.0 0.0
2 2 0.0 1.0 0.0
3 3 0.0 0.0 1.0
4 4 1.0 0.0 0.0
5 5 0.0 1.0 0.0
df2[['data1']].join(dummies)#Series没有join
data1 key_a key_b key_c
0 0 0.0 1.0 0.0
1 1 1.0 0.0 0.0
2 2 0.0 1.0 0.0
3 3 0.0 0.0 1.0
4 4 1.0 0.0 0.0
5 5 0.0 1.0 0.0
df2[['data1']]#选出的是DataFrame
data1
0 0
1 1
2 2
3 3
4 4
5 5
df2['data1']#选出的是Series
0    0
1    1
2    2
3    3
4    4
5    5
Name: data1, dtype: int64

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python-pandas-Series和DataFrame的基本功能

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转载自blog.csdn.net/LY_ysys629/article/details/73873601