版权声明:本文为博主原创文章,未经博主允许不得转载。 https://blog.csdn.net/jerry81333/article/details/79146385
题目:
Given a string, find the length of the longest substring without repeating characters.
Examples:
Given "abcabcbb"
, the answer is "abc"
, which the length is 3.
Given "bbbbb"
, the answer is "b"
, with the length of 1.
Given "pwwkew"
, the answer is "wke"
, with the length of 3. Note that the answer must be a substring, "pwke"
is a subsequence and not a substring.
简单来说,就是找不重复的最大字符串。
思路:
1. 最简单的莫过于从第一个字符开始找最大非重复字符串,找到最后个字符,简单粗暴,可以实现,但是会卡在时间复杂度上面。
2. 另一种就是使用队列的思路,start为队首,end为队尾,从串的开头开始,不重复则队列+1,重复则从start中慢慢pop出去,直到找到并pop出重复的字符。start-end为不重复的最大字符串值。
复杂度O(n) + O(n) = O(n)
代码:
class Solution(object):
def lengthOfLongestSubstring(self, s):
"""
:type s: str
:rtype: int
"""
i=0
j=0
max=0
list=[]
while True:
while j<len(s):
if s[j] in list:
break
list.append(s[j])
j+=1
if max<j-i:
max=j-i
if j>=len(s):
break
while i<j:
key = list.pop(0)
i+=1
if key == s[j]:
break
return max