python统计列表中某个元素出现次数

users = ['bobby1', 'bobby2', 'bobby3', 'bobby1', 'bobby2', 'bobby2' ]统计各个元素出现次数

1.传统方法

user_dict = {}
for user in users:
    if user not in user_dict:
        user_dict[user] = 1
    else:
        user_dict[user] +=1

2.用setdefault方法,当元素没有在字典中出现时设置一个默认值

for user in users:
    user_dict.setdefault(user, 0) # 代码简洁、且性能高
    user_dict[user] +=1
print user_dict

3.用defaultdict,defaultdict接收一个可调用变量来做初始化

from collections import defaultdict
# 进一步优化,代码量更少
default_dict = defaultdict(int) # 传一个可调用的对象 list int
for user in users:
    default_dict[user] +=1

提高:已知s,输出结果为[('blue', [2, 4]), ('red', [1]), ('yellow', [1, 3])]

s = [('yellow',1), ('blue', 2), ('yellow', 3), ('blue', 4), ('red', 1)]
d = defaultdict(list)
for color, c in s:
    d[color].append(c)
print d.items()

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转载自blog.csdn.net/liuxiao19890212/article/details/83895367