26-remove-duplicates-from-sorted-array

题目描述:

Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.

Example 1:

Given nums = [1,1,2],

Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively.

It doesn't matter what you leave beyond the returned length.

Example 2:

Given nums = [0,0,1,1,1,2,2,3,3,4],

Your function should return length = 5, with the first five elements of nums being modified to 0, 1, 2, 3, and 4 respectively.

It doesn't matter what values are set beyond the returned length.

Clarification:

Confused why the returned value is an integer but your answer is an array?

Note that the input array is passed in by reference, which means modification to the input array will be known to the caller as well.

Internally you can think of this:

// nums is passed in by reference. (i.e., without making a copy)
int len = removeDuplicates(nums);

// any modification to nums in your function would be known by the caller.
// using the length returned by your function, it prints the first len elements.
for (int i = 0; i < len; i++) {
    print(nums[i]);
}

代码解答:

package com.jack.algorithm;

/**
 * create by jack 2018/11/4
 *
 * @author jack
 * @date: 2018/11/4 22:16
 * @Description:
 * 数组里面不同元素的个数
 */
public class RemoveDuplicatesFromSortedArray {

    /**
     * 题目描述:
     * https://leetcode.com/problems/remove-duplicates-from-sorted-array/
     *
     * @param nums
     * @return
     */
    public static int removeDuplicates(int[] nums) {
        if (nums.length == 0) return 0;
        int i = 0;
        for (int j = 1; j < nums.length; j++) {
            if (nums[j] != nums[i]) {
                i++;
                nums[i] = nums[j];
            }
        }
        return i + 1;
    }



    public static void main(String[] args) {
        int[] nums1 =new int[]{1,1,2};
        //int[] nums1 =new int[]{0,0,1,1,1,2,2,3,3,4};
        //int[] nums1 =new int[]{0,0,1,1,1,2,2,3,3,4};

        int num = removeDuplicates(nums1);
        System.out.println("num = "+num);
    }
}

源码地址:

源码

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转载自blog.csdn.net/wj903829182/article/details/83757119
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