简单结构体练习

项目：创建一个公司员工的结构体，储存员工的姓名、工龄、年龄。
要求：在主函数里创建5个结构体数组，从终端输入信息，分别以工龄排序和年龄排序输出，排序方式自定。
代码如下：

#include <iostream>
#include<string.h>
#include<stdio.h>
//创建员工信息的结构体
struct Staff
{
	char name[20];
	int seniority;
	int age;
};
//录入员工信息
void scanfStaInf(struct Staff* information)
{
	printf("请输入员工姓名：");
	scanf("%s", information->name);
	printf("请输入员工工龄：");
	scanf("%d", &information->seniority);
	printf("请输入员工年龄：");
	scanf("%d",&information->age);
	printf("---------------\n");
}
//循环录入
void scanfStaInf1(struct Staff* array,int elength)
{
	for (int i = 0; i < elength; i++)
	{
		scanfStaInf(&array[i]);//调用录入员工信息的函数
	}
}
//比较年龄，由小到大
int compareAge(struct Staff*p1, struct Staff*p2)
{
	if (p1->age == p2->age)
	{
		if (p1->seniority > p2->seniority)
		{
			return p1->seniority > p2->seniority;
		}
	}
	return p1->age > p2->age;
}
//比较工龄,由小到大
int compareSeniority(struct Staff* p1, struct Staff* p2)
{
	if (p1->seniority == p2->seniority)
	{
		if (p1->age>p2->age)
		{
			return p1->age > p2->age;
		}
	}
	return p1->seniority >p2->seniority;
}
//使用冒泡排序
void orderBySta(struct Staff* arry, int elength, int (*compareSeniority)(struct Staff* p1, struct Staff* p2))
{
	for (int i = 0; i < elength-1; i++)
	{
		for (int j = 0; j < elength-1-i; j++)
		{
			if (compareSeniority(&arry[j],&arry[j+1]))
			{
				struct Staff temp = arry[j];
				arry[j] = arry[j + 1];
				arry[j + 1] = temp;
			}
		}
	}
}
//打印信息
void printStaInf(struct Staff Print)
{
	printf("name:%s seniority:%d age:%d\n", Print.name, Print.seniority, Print.age);
}
//循环数组
void circulation(struct Staff* Print,int length)
{
	for (int i = 0; i < length; i++)
	{
		printStaInf(Print[i]);//调用打印信息的函数
	}
	printf("----------------\n");
}

int main()
{
	//创建5个结构体数组
    struct Staff Information[5];
    //录入员工信息
    scanfStaInf1(Information, 5);
	//调用排序,按工龄排序，工龄相同，则看年龄
	orderBySta(Information, 5, compareSeniority);
	//读取员工信息
	circulation(Information,5);	
	//调用排序，按年龄排序，年龄相同，看工龄
	orderBySta(Information, 5, compareAge);
	//读取员工信息
	circulation(Information, 5);
	

}
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