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1、现在有一个列表,list1 = [‘key1’,‘key2’,‘key3’],把他转为这样的字典:{‘key1’:‘1’,‘key2’:‘2’,‘key3’:‘3’}
方法:再构造一个列表list2 = [‘1’,‘2’,‘3’],使用zip转换为元组后,在将元组转换为字典
list1 = ['key1','key2','key3']
list2 = ['1','2','3']
dict(zip(list1,list2))
{'key1':'1','key2':'2','key3':'3'}
2、将嵌套列表转为字典,有两种方法,
new_list= [['key1','value1'],['key2','value2'],['key3','value3']]
dict(list)
{'key3': 'value3', 'key2': 'value2', 'key1': 'value1'}
或者这样:
new_list= [['key1','value1'],['key2','value2'],['key3','value3']]
new_dict = {}
for i in new_list:
new_dict[i[0]] = i[1] #字典赋值,左边为key,右边为value
new_dict
{'key3': 'value3', 'key2': 'value2', 'key1': 'value1'}