算法刷题(11)--统计一个数字在排序数组中出现的次数。

算法刷题(11)--统计一个数字在排序数组中出现的次数。


方法一:(暴力破解)

package p2;

/**
 * 题目描述:
 * 统计一个数字在排序数组中出现的次数。
 * @author Guozhu Zhu
 * @date 2018/4/25
 * @version 1.0
 *
 */
public class Test01 {
	
	public static void main(String[] args) {
		int[] array = {1, 2, 3, 3, 3, 4, 5};
		System.out.println(getNumberOfK(array, 3));
	}
	
	public static int getNumberOfK(int[] arr, int k) {
		int count = 0;
		for (int i = 0; i < arr.length; i++) {
			if (arr[i] == k) {
				count++;
			}
		}
		return count;
	}

}

方法二(二分查找算法):

package p2;

/**
 * 二分查找算法
 * @author Guozhu Zhu
 * @date 2018/4/25
 * @version 1.0
 *
 */
public class Test02 {
	    
	public static void main(String[] args) {
		int[] array = {1, 2, 3, 3, 3, 4, 5};
		System.out.println(GetNumberOfK(array, 3));
	}
	
	public static int GetNumberOfK(int[] array , int k) {
	        int i = getFirstK(array, k, 0, array.length-1);
	        int j = getLastK(array, k, 0, array.length-1);
	        if (i != -1 && j != -1)
	            return j-i+1;
	        return 0;
	}

    public static int getFirstK(int[] array , int k, int low, int high) {
        while (low <= high) {
        	int mid = (low+high)/2;
            if (k > array[mid]) {
                low = mid + 1;
            } else if (k < array[mid]) {
                high = mid - 1;
            } else if (mid-1 >= 0 && array[mid-1] == k) {// 找“头”
                high = mid - 1;
            } else {
                return mid;
            }
        }
        return -1;
    }

    public static int getLastK(int[] array , int k, int low, int high) {
        while (low <= high) {
        	int mid = (low + high)/2;
            if (k > array[mid]) {
                low = mid + 1;
            } else if (k < array[mid]) {
                high = mid - 1;
            } else if (mid+1 < array.length && array[mid+1] == k) {// 找“尾”
                low = mid + 1;
            } else {
                return mid;
            }
        }
        return -1;
    }
    
}

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转载自blog.csdn.net/weixin_37770023/article/details/80078541