1.map：
(1)可以用于遍历数组中每一个元素，将每个元素自身与自身相加，然后返回一个新的数组：
let numberArr=[1,2,3,4,5,6]
//方式一：
let result1=numberArr.map { (number:Int) -> Int in
return number+number
}
print("result1=\(result1)")
//方式二:
let result2=numberArr.map{ number in
return number+number
}
print("result2=\(result2)")
//方式三:
let result3=numberArr.map{$0+$0}
print("result3=\(result3)")
(2)可以用于过滤符合条件的数组结果：
func mapTest2(){
let numberArr=[1,2,3,4,5,6]
let result=numberArr.map{ number ->Int? in
guard number%2 != 0 else{
return number
}
return nil
}
print(result)
}
2.FlatMap:
(1)不会返回数组中不存在的nil，同时把Optional解包:
func flatMapTest1(){
let numberArr=[1,2,3,4,5,6]
let result=numberArr.flatMap{ number ->Int? in
guard number%2 != 0 else{
return number
}
return nil
}
print(result)
}
(2)合并两个数组:
func flatMapTest2(){
let nameArr=["张三","李四","王五"]
let ageArr=[20,40,23]
let result=ageArr.flatMap{ age in
nameArr.map{name in
(name,age)
}
}
print(result)
}
3.Filter 可以把数组中的不符合条件的值过滤掉，返回一个新的数组:
func filterTest(){
let numberArr=[1,2,3,4,5,6]
let result=numberArr.filter{$0%2 != 0}
print(result)
}
4.reduce:
(1)计算数组元素的和
func filterTest(){
let numberArr=[1,2,3,4,5,6]
let result=numberArr.reduce(0){total,number in
return total + number
}
print(result)
}
(2)将一个数组合并成一个字符串输出:
func filterTest(){
let numberArr=[1,2,3,4,5,6]
//方式一：
let result1:String=numberArr.reduce(""){number1,number2 in
return "\(number1)" + "\(number2)"
}
print(result1)
//方式二：
let result2:String=numberArr.reduce(""){"\($0)"+"\($1)"}
print(result2)
}