[leetcode]-7. Reverse Integer(C语言)

Given a 32-bit signed integer, reverse digits of an integer.

Example 1:

Input: 123
Output:  321

Example 2:

Input: -123
Output: -321

Example 3:

Input: 120
Output: 21

Note:
Assume we are dealing with an environment which could only hold integers within the 32-bit signed integer range. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

主要注意的是溢出问题:如果溢出,则系统只取低32位,会造成结果错误。

int reverse(int x) {
    int result,sum=0;
    int b;
    while(x)
    {
        b=x%10;
        result=sum*10+b;
        x=x/10;
        if((result-b)/10!=sum)         //判断是否溢出
            return 0;
        sum=result;
            
    }
    if(sum>2147483648)
        return 0;
    return sum;
}

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转载自blog.csdn.net/shen_zhu/article/details/79613599