class Solution:
def isAnagram(self, s, t):
"""
:type s: str
:type t: str
:rtype: bool
"""
dp1=[0]*26
dp2=[0]*26
if len(s) != len(t):
return False
for c1 in s:
dp1[ord(c1)-97]+=1
for c2 in t:
dp2[ord(c2)-97]+=1
if dp1==dp2:
return True
else:
return False
python leetcode 242. Valid Anagram
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转载自blog.csdn.net/Neekity/article/details/85104424
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