3道面试题

1. 写一个函数, 输入一个字符串, 返回倒序排列的结果: 如: string_reverse(‘abcdef’),
返回: ‘fedcba’ (请采用多种方法实现)

s = 'abcdef'
l = list(s)
l.sort(reverse=True)
s = ''.join(l)
print(s)

s = 'abcdef'
s1 = ''
for i in s[::-1]:
    s1 += i
print(s1)

s = 'abcdef'
l = []
[l.append(i) for i in s[::-1]]
s = ''.join(l)
print(s)

2. 请用自己的算法, 合并如下两个list按大小排序, 并去除重复的元素:
list1 = [2, 3, 8, 4, 9, 5, 6]
list2 = [5, 6, 10, 17, 11, 2]

l = []
list1 = [2, 3, 8, 4, 9, 5, 6]
list2 = [5, 6, 10, 17, 11, 2]
l = list1 + list2
print(list(set(l)))

list1 = [2, 3, 8, 4, 9, 5, 6]
list2 = [5, 6, 10, 17, 11, 2]
[list1.append(i) for i in list2 if i not in list1]
print(list1)

l = [2, 3, 8, 4, 9, 5, 6, 10, 17, 11]
print(sorted(l))

l = [2, 3, 8, 4, 9, 5, 6, 10, 17, 11]
l.sort()
print(l)

3.python 如何捕获异常

def num(s):
    try:
        for i in s:
            print(i)
    except Exception as e:
        print(e)
    finally:
        print('执行完毕')
num('kkk')

def num1(s):
    if type(s) == int:
        raise ValueError('s is not int')
    else:
        for i in s:
            print(i)

try:
    num1('wang')
except ValueError as e:
    raise  TypeError('type error')


def num2(s):
    assert type(s) != int, 's is not int....'
    for i in s:
        print(i)
num2('wang')