Given N integers, you are supposed to find the smallest positive integer that is NOT in the given list.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤105). Then N integers are given in the next line, separated by spaces. All the numbers are in the range of int.
Output Specification:
Print in a line the smallest positive integer that is missing from the input list.
Sample Input:
10
5 -25 9 6 1 3 4 2 5 17
Sample Output:
7
设一个数组记录出现过的小于10^5的正数
#include<iostream>
#include<vector>
#include<cstdio>
using namespace std;
std::vector<int> v(1000000,0);
int main(){
int n;
scanf("%d",&n);
for(int i=0;i<n;i++){
int x;
scanf("%d",&x);
if(x>0&&x<1000000)
v[x]=1;
}
for(int i=1;i<v.size();i++){
if(v[i]==0){
cout<<i;
break;
}
}
}