leetcode185. 部门工资前三高的员工

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Employee 表包含所有员工信息，每个员工有其对应的 Id, salary 和 department Id 。

±—±------±-------±-------------+
| Id | Name | Salary | DepartmentId |
±—±------±-------±-------------+
| 1 | Joe | 70000 | 1 |
| 2 | Henry | 80000 | 2 |
| 3 | Sam | 60000 | 2 |
| 4 | Max | 90000 | 1 |
| 5 | Janet | 69000 | 1 |
| 6 | Randy | 85000 | 1 |
±—±------±-------±-------------+
Department 表包含公司所有部门的信息。

±—±---------+
| Id | Name |
±—±---------+
| 1 | IT |
| 2 | Sales |
±—±---------+
编写一个 SQL 查询，找出每个部门工资前三高的员工。例如，根据上述给定的表格，查询结果应返回：

±-----------±---------±-------+
| Department | Employee | Salary |
±-----------±---------±-------+
| IT | Max | 90000 |
| IT | Randy | 85000 |
| IT | Joe | 70000 |
| Sales | Henry | 80000 |
| Sales | Sam | 60000 |
±-----------±---------±-------+

Write your MySQL query statement below

SELECT
d. NAME AS Department,
e. NAME AS Employee,
e.salary AS Salary
FROM
employee AS e
INNER JOIN department AS d ON e.DepartmentId = d.id
WHERE
(
SELECT
count(DISTINCT salary)
FROM
employee
WHERE
salary > e.salary
AND departmentid = e.DepartmentId
) < 3
ORDER BY
e.departmentid,
Salary DESC