编号转换

#include<stdio.h>
#include<string.h>
void strRev(char *s);
int main()
{
    int T,i,a=0,b=0,sum1,sum2,j,sum;
    char ch1[1000000],ch2[1000000],c='0',d='0',e[100]={},w[100]={};
    scanf("%d",&T);
    getchar();
    for(i=0;i<T;i++)
    {
        gets(ch1);
        if('0'>ch1[1]||ch1[1]>'9')
        {
            j=0;
            sum1=0;
            while('0'>ch1[j]||ch1[j]>'9')
            {
                sum1=sum1*26+ch1[j]-'A'+1;
                j=j+1;
            }
            sum2=0;
            while('0'<=ch1[j]&&ch1[j]<='9')
            {
                sum2=sum2*10+ch1[j]-'0';
                j=j+1;
            }
            printf("%c%d%c%d\n",'R',sum2,'C',sum1);
        }
        else
        {
            i=1;
            sum1=0;
            while('0'<=ch1[i]&&ch1[i]<='9')
            {
                sum1=sum1*10+ch1[i]-'0';
                i=i+1;
            }
            i=i+1;
            sum2=0;
            while('0'<=ch1[i]&&ch1[i]<='9')
            {
                sum2=sum2*10+ch1[i]-'0';
                i=i+1;
            }
            sum=sum2;
            while(sum2%26)
            {
                a=sum2%26+'A'-1;
                w[0]=(char)a;
                strncat(e,w,1);
                sum2=sum2/26;
            }
            strRev(e);
            printf("%s%d\n",e,sum1);
        }

    }


}
void strRev(char *s)
{
    char temp, *end = s + strlen(s) - 1;
    while( end > s)
    {
        temp = *s;
        *s = *end;
        *end = temp;
        --end;
        ++s;
    }
}