关于静态成员变量在派生类中重新声明

引用自https://blog.csdn.net/digu/article/details/1837559 修改

基类和派生类都声明了同名静态成员,它们的地址是连续的,如下代码,可以通过指针偏移互相访问;

#include<iostream>
class base
{
    int mx;
public:
    static int xxx[];
    static void fun(int x)
    {
        xxx[0]=x;
    }
    base(int x):mx(x){}
    friend std::ostream& operator<<(std::ostream& ,base&);
};
int base::xxx[]={1,2,3};


class test:public base
{
    public:
    test(int x):base(x){}


    static int xxx[];
    static void fun(int x)
    {
        xxx[0]=x;
    }


};
int test::xxx[]={4,5};


std::ostream& operator<<(std::ostream& os,base& s)
{
    os<<s.mx;
    return os;
}
int main()
{
    test x(321);
    base y(123);


    std::cout<<&base::xxx[0]<<std::endl;
    std::cout<<&test::xxx[0]<<std::endl;    
    
    std::cout<<base::xxx[0]<<std::endl;
    std::cout<<base::xxx[1]<<std::endl;
    std::cout<<base::xxx[2]<<std::endl;
    std::cout<<base::xxx[3]<<std::endl;
    std::cout<<base::xxx[4]<<std::endl;


    std::cout<<test::xxx[-3]<<std::endl;
    std::cout<<test::xxx[-2]<<std::endl;
    std::cout<<test::xxx[-1]<<std::endl;
    std::cout<<test::xxx[0]<<std::endl;
    std::cout<<test::xxx[1]<<std::endl;
    
    return 0;

}

输出结果:


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转载自blog.csdn.net/weixin_41587767/article/details/80084744