如有失误之处,还恳请指教!!!
//arrobj.cpp -- functions with array objects
#include <iostream>
#include <array>
#include <string>
const int Seasons = 4;
using namespace std;
//使用array对象来存储四个季度,表示这个数组含有4个string类型的元素,数组名称为Sname
const array<string, Seasons> Snames =
{"Spring", "Summer", "Fall", "Winter"};
//函数原型:没有返回值,参数为array对象的指针
void fill(array<double, Seasons> *pa);
//函数原型:没有返回值,参数为array对象的值
void show(array<double, Seasons> da);
int main()
{
//定义了一个array对象的数组,该数组含有4个double类型的元素
//该数组名称为expences
array<double, 4> expenses;
//调用函数,并将数组expences的地址传递给该被调函数
//按地址传递
fill(&expenses);
//调用函数,并将数组expenses作为参数传递给该函数
//按值传递
show(expenses);
// std::cin.get();
// std::cin.get();
return 0;
}
void fill(array<double, Seasons> *pa)
{
for (int i = 0; i < Seasons; i++)
{
cout << "Enter " << Snames[i] << " expenses: ";
//在上面的代码中将&expenses作为参数传递给pa,因此*pa相当于expenses
//cin >> (*pa)[i] 相当于 cin >> expences[i];
cin >> (*pa)[i];
}
}
void show(array<double, Seasons> da)
{
double total = 0.0;
cout << "\nEXPENSES\n";
for (int i = 0; i < Seasons; i++)
{
cout << Snames[i] << ": $" << da[i] << '\n';
total += da[i];
}
cout << "Total: $" << total << '\n';
}