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package chap03;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.stream.Collectors;
public class FlatMap {
public static void main(String[] args) {
//扁平化流
//找出数组中唯一的字符
String[] strArray = {"hello", "world"};
//具体实现
List<String> res = Arrays.stream(strArray)
.map(w -> w.split(""))
.flatMap(Arrays::stream)
.distinct()
.collect(Collectors.toList());
System.out.println(res);
//TODO 案例
System.out.println("--------------------------------");
//Demo1:给定数组,返回数组平方和(直接使用映射)
//[1,2,3,4]=>[1,4,9,16]
Integer[] nums1 = {1, 2, 3, 4};
List<Integer> nums1List = Arrays.asList(nums1);
List<Integer> res1 = nums1List.stream().map(i -> i * i).collect(Collectors.toList());
System.out.println(res1);
System.out.println("--------------------------------");
//Demo2:给定两数组,返回数组对
//[1,2,3],[3,4]=>[1,3],[1,4],[2,3],[2,4],[3,3],[3,4]
Integer[] nums2 = {1, 2, 3};
Integer[] nums3 = {3, 4};
List<Integer> nums2List = Arrays.asList(nums2);
List<Integer> nums3List = Arrays.asList(nums3);
//使用2个map嵌套过滤
List<int[]> res2 = nums2List.stream().flatMap(i -> nums3List.stream().map(j -> new int[]{i, j})).collect(Collectors.toList());
System.out.println(res2.size());
System.out.println("--------------------------------");
//Demo3:针对Demo2和Demo1组合返回总和能被3整除的数对
//(2,4)和(3,3)是满足条件的
List<int[]> res3 = nums2List.stream().flatMap(i -> nums3List.stream().filter(j -> (i + j) % 3 == 0).map(j -> new int[]{i, j})).collect(Collectors.toList());
System.out.println(res3.size());
}
}
控制台输出结果:
总结:关于流的具体应用测试如下:
Trasaction类:
package chap03.StreamDemo;
public class Transaction {
private final Trader trader;
private final int year;
private final int value;
public Transaction(Trader trader, int year, int value) {
this.trader = trader;
this.year = year;
this.value = value;
}
public Trader getTrader() {
return trader;
}
public int getYear() {
return year;
}
public int getValue() {
return value;
}
@Override
public String toString() {
return "{"+this.trader+","+this.year+","+this.value+"}";
}
}
Trader类:
package chap03.StreamDemo;
public class Trader {
private final String name;
private final String city;
public Trader(String name, String city) {
this.name = name;
this.city = city;
}
public String getName() {
return name;
}
public String getCity() {
return city;
}
@Override
public String toString() {
return "Trder:" + this.name + " in " + this.city;
}
}
Main测试主类:
package chap03.StreamDemo;
import java.util.Arrays;
import java.util.Comparator;
import java.util.List;
import java.util.Optional;
import java.util.stream.Collectors;
import static java.util.Comparator.comparing;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;
public class Main {
public static void main(String[] args) {
Trader raoul = new Trader("Raou1", "Cambridge");
Trader mario = new Trader("Mario", "Milan");
Trader alan = new Trader("Alan", "Cambridge");
Trader brian = new Trader("Brian", "Cambridge");
List<Transaction> transactions = Arrays.asList(
new Transaction(brian, 2011, 300),
new Transaction(raoul, 2012, 1000),
new Transaction(raoul, 2011, 400),
new Transaction(mario, 2012, 710),
new Transaction(mario, 2012, 700),
new Transaction(alan, 2012, 950)
);
//1.找出2011年的所有交易并按交易额排序(从低到高)
List<Transaction> tr2011 = transactions.stream().filter(transaction -> transaction.getYear() == 2011)
.sorted(Comparator.comparing(Transaction::getValue))
.collect(toList());
System.out.println(tr2011);
//2.交易员都在哪些不同城市工作过
List<String> cities = transactions.stream().map(transaction -> transaction.getTrader().getCity())
.distinct()
.collect(toList());
System.out.println(cities);
//3.查找所有来自剑桥的交易员,并按姓名排序
List<Trader> traders = transactions.stream().map(Transaction::getTrader)
.filter(trader -> trader.getCity().equals("Cambridge"))
.distinct()
.sorted(comparing(Trader::getName))
.collect(toList());
System.out.println(traders);
//4.返回所有交易员的姓名字符串,按字母顺序排序
String traderStr = transactions.stream().map(transaction -> transaction.getTrader().getName())
.distinct()
.sorted()
.reduce("", (str1, str2) -> str1 + str2);
System.out.println(traderStr);
//因为上述存在a和b字符串反复拼接比较,所以改进方案如下:
String traderStr2 = transactions.stream().map(transaction -> transaction.getTrader().getName())
.distinct()
.sorted()
.collect(joining());
//5.有没有交易员是在米兰工作的
boolean milanBased = transactions.stream()
.anyMatch(transaction -> transaction.getTrader().getCity().equals("Milan"));
System.out.println(milanBased);
//6.打印生活在剑桥的交易员的所有交易额
transactions.stream().filter(transaction -> transaction.getTrader().getCity().equals("Cambridge"))
.map(Transaction::getValue)
.forEach(System.out::println);
//7.所有交易中,最高的交易额是多少?
Optional<Integer> highestValue = transactions.stream().map(Transaction::getValue).reduce(Integer::max);
System.out.println(highestValue);
//8.找到交易额最小的交易
Optional<Integer> smallestValue = transactions.stream().map(Transaction::getValue).reduce(Integer::min);
//或者,Optional为容器类
Optional<Transaction> smallestValue2 = transactions.stream().reduce((t1, t2) -> t1.getValue() < t2.getValue() ? t1 : t2);
System.out.println(smallestValue);
System.out.println(smallestValue2);
}
}