[蓝桥杯][基础练习VIP]报时助手

版权声明:转自翠羽黄衫的博客! https://blog.csdn.net/ac1085589289/article/details/86623148

题目描述

给定当前的时间,请用英文的读法将它读出来。

时间用时h和分m表示,在英文的读法中,读一个时间的方法是:

如果m为0,则将时读出来,然后加上“o’clock”,如3:00读作“three o’clock”。

如果m不为0,则将时读出来,然后将分读出来,如5:30读作“five thirty”。

时和分的读法使用的是英文数字的读法,其中0~20读作:

0:zero, 1: one, 2:two, 3:three, 4:four, 5:five, 6:six, 7:seven, 8:eight, 9:nine, 10:ten, 11:eleven, 12:twelve, 13:thirteen, 14:fourteen, 15:fifteen, 16:sixteen, 17:seventeen, 18:eighteen, 19:nineteen, 20:twenty。

30读作thirty,40读作forty,50读作fifty。

对于大于20小于60的数字,首先读整十的数,然后再加上个位数。如31首先读30再加1的读法,读作“thirty one”。

按上面的规则21:54读作“twenty one fifty four”,9:07读作“nine seven”,0:15读作“zero fifteen”。
输入
输入包含两个非负整数h和m,表示时间的时和分。非零的数字前没有前导0。h小于24,m小于60。
输出
输出时间时刻的英文。
样例输入

0 15

样例输出

zero fifteen

#include<iostream>
using namespace std;
int main()
{
	int h,m;
	cin>>h>>m;
	switch(h)
	{
		case 0:cout<<"zero";break;
		case 1:cout<<"one";break;
		case 2:cout<<"two";break;
		case 3:cout<<"three";break;
		case 4:cout<<"four";break;
		case 5:cout<<"five";break;
		case 6:cout<<"six";break;
		case 7:cout<<"seven";break;
		case 8:cout<<"eight";break;
		case 9:cout<<"nine";break;
		case 10:cout<<"ten";break;
		case 11:cout<<"eleven";break;
		case 12:cout<<"twelve";break;
		case 13:cout<<"thirteen";break;
		case 14:cout<<"fourteen";break;
		case 15:cout<<"fifteen";break;
		case 16:cout<<"sixteen";break;
		case 17:cout<<"seventeen";break;
		case 18:cout<<"eighteen";break;
		case 19:cout<<"nineteen";break;
		case 20:cout<<"twenty";break;
		case 21:cout<<"twenty one";break;
		case 22:cout<<"twenty two";break;
		case 23:cout<<"twenty three";break;
		default:break;
	}
	cout<<" ";
	if(m<24)
	{
		switch(m)
		{
		case 0:cout<<"o'clock";break;
		case 1:cout<<"one";break;
		case 2:cout<<"two";break;
		case 3:cout<<"three";break;
		case 4:cout<<"four";break;
		case 5:cout<<"five";break;
		case 6:cout<<"six";break;
		case 7:cout<<"seven";break;
		case 8:cout<<"eight";break;
		case 9:cout<<"nine";break;
		case 10:cout<<"ten";break;
		case 11:cout<<"eleven";break;
		case 12:cout<<"twelve";break;
		case 13:cout<<"thirteen";break;
		case 14:cout<<"fourteen";break;
		case 15:cout<<"fifteen";break;
		case 16:cout<<"sixteen";break;
		case 17:cout<<"seventeen";break;
		case 18:cout<<"eighteen";break;
		case 19:cout<<"nineteen";break;
		case 20:cout<<"twenty";break;
		case 21:cout<<"twenty one";break;
		case 22:cout<<"twenty two";break;
		case 23:cout<<"twenty three";break;
		default:break;
		}
	}
	else if(m>23)
	{	int m1,m2; 
		m1=m/10;
		m2=m%10;
		switch(m1)
		{
			case 2:cout<<"twenty";break;
			case 3:cout<<"thirty";break;
			case 4:cout<<"forty";break;
			case 5:cout<<"fifty";break;
			defaut:break;
		}
		if(m2)
		{
			cout<<" ";
			switch(m2)
			{
		case 1:cout<<"one";break;
		case 2:cout<<"two";break;
		case 3:cout<<"three";break;
		case 4:cout<<"four";break;
		case 5:cout<<"five";break;
		case 6:cout<<"six";break;
		case 7:cout<<"seven";break;
		case 8:cout<<"eight";break;
		case 9:cout<<"nine";break;
		default:break;	
			}
		} 

	}
	
	return 0;
}

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转载自blog.csdn.net/ac1085589289/article/details/86623148
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