数列有序#acm刷题

数列有序!

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 121456 Accepted Submission(s): 50114

Problem Description
有n(n<=100)个整数,已经按照从小到大顺序排列好,现在另外给一个整数x,请将该数插入到序列中,并使新的序列仍然有序。

Input
输入数据包含多个测试实例,每组数据由两行组成,第一行是n和m,第二行是已经有序的n个数的数列。n和m同时为0标示输入数据的结束,本行不做处理。

Output
对于每个测试实例,输出插入新的元素后的数列。

Sample Input

3 3
1 2 4
0 0

Sample Output

1 2 3 4

题目分析:
很简单的排序,注意的是数组大小不确定,所以用动态数组。

AC的c++代码
#include<iostream>
using namespace std;
int main()
{
	int n, m;
	while (cin >> n >> m && n != 0 && m != 0)
	{
		int*a = new int[n+1];
		for (int i = 0; i < n; i++)
		{
			cin >> a[i];
		}
		a[n] = m;
		for (int i = 0; i < n + 1; i++)
		{
			if (a[n] < a[i])
			{
				int temp = 0;
				temp = a[n];
				a[n] = a[i];
				a[i] = temp;
			}
		}
		bool work = 0;
		for (int i = 0; i < n + 1; i++)
		{
			if (work)cout << " ";
			cout << a[i];
			work = 1;
		}
		cout << endl;
		delete[]a;
		a = NULL;
	}
	return 0;
}

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转载自blog.csdn.net/weixin_43316754/article/details/85040995
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