【LeetCode009】Palindrome Number

class Solution {
public:
    bool isPalindrome(int x) {
        if(x < 0)
            return 0;//负数直接pass
        int num = 1;
        while(x/num > 9)
            num *= 10;//看看是几位数
        while(x != 0){//终止条件
            int front = x/num;
            int back = x%10;
            if(front != back)
                return 0;
            x = (x%num)/10;//灵魂，%和/别搞反了
            num /= 100;//迭代
        }
        return 1;
    }
};