void print()
{
string s;
long long nn = num;
if (nn == 0)
s = "0";
while (nn)
{
char c;
if (nn%r <= 9)
c = (nn%r) + '0';
else
c = (nn%r - 10) + 'A';
nn /= r;
s = c + s;
}
cout << s << endl;
}
进制转换,10进制转换为任意进制
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转载自blog.csdn.net/yang8627/article/details/88177343
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