HDOJ 2015 偶数求和

#include<iostream>

using namespace std;

int main() {
    int n, m;
    while (cin >> n && cin >> m) {
        int sum = 0;
        int start = 2;
        for (int i = 1;i <= n;i++) {
            sum += start;
            start += 2;
            if (i % m == 0) {
                cout << sum / m;
                sum = 0;
                if (i != n) cout << " ";
            }
        }
        if (sum != 0) {
            cout << sum / (n%m);
        }
        cout << endl;
    }
    return 0;
}

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转载自www.cnblogs.com/Mered1th/p/10564334.html