等保测评中提出：
对Oracle数据库 数据库复杂性函数Password_verfy_function 的值为Null，未启用复杂度要求，数据库用户登录失败次数 Failied_Login_Attemps 值为0，password_lock_time 值为0. 数据库未设置 IDLE_TIME 超时锁定，等一系列跟数据库有关的安全设置。
一直没敢操刀
是因为觉得很难。
百度了下，so easy~~
简言之:
第一步：写函数
第二步：做设置
第三步：check
以sys用户，oradba 身份登录到数据库
接着直接写如下内容:
CREATE OR REPLACE FUNCTION verify_function_11G
(username varchar2,
password varchar2,
old_password varchar2)
RETURN boolean IS
n boolean;
m integer;
differ integer;
isdigit boolean;
ischar boolean;
ispunct boolean;
db_name varchar2(40);
digitarray varchar2(20);
punctarray varchar2(25);
chararray varchar2(52);
i_char varchar2(10);
simple_password varchar2(10);
reverse_user varchar2(32);
BEGIN
digitarray:= ‘0123456789’;
chararray:= ‘abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ’;
– Check for the minimum length of the password
IF length(password) < 8 THEN
raise_application_error(-20001, ‘Password length less than 8’);
END IF;
– Check if the password is same as the username or username(1-100)
IF NLS_LOWER(password) = NLS_LOWER(username) THEN
raise_application_error(-20002, ‘Password same as or similar to user’);
END IF;
FOR i IN 1..100 LOOP
i_char := to_char(i);
if NLS_LOWER(username)|| i_char = NLS_LOWER(password) THEN
raise_application_error(-20005, ‘Password same as or similar to user name ‘);
END IF;
END LOOP;
– Check if the password is same as the username reversed
FOR i in REVERSE 1..length(username) LOOP
reverse_user := reverse_user || substr(username, i, 1);
END LOOP;
IF NLS_LOWER(password) = NLS_LOWER(reverse_user) THEN
raise_application_error(-20003, ‘Password same as username reversed’);
END IF;
– Check if the password is the same as server name and or servername(1-100)
select name into db_name from sys.v$database;
if NLS_LOWER(db_name) = NLS_LOWER(password) THEN
raise_application_error(-20004, ‘Password same as or similar to server name’);
END IF;
FOR i IN 1..100 LOOP
i_char := to_char(i);
if NLS_LOWER(db_name)|| i_char = NLS_LOWER(password) THEN
raise_application_error(-20005, ‘Password same as or similar to server name ‘);
END IF;
END LOOP;
– Check if the password is too simple. A dictionary of words may be
– maintained and a check may be made so as not to allow the words
– that are too simple for the password.
IF NLS_LOWER(password) IN (‘welcome1’, ‘database1’, ‘account1’, ‘user1234’, ‘password1’, ‘oracle123’, ‘computer1’, ‘abcdefg1’, ‘change_on_install’) THEN
raise_application_error(-20006, ‘Password too simple’);
END IF;
– Check if the password is the same as oracle (1-100)
simple_password := ‘oracle’;
FOR i IN 1..100 LOOP
i_char := to_char(i);
if simple_password || i_char = NLS_LOWER(password) THEN
raise_application_error(-20007, ‘Password too simple ‘);
END IF;
END LOOP;
– Check if the password contains at least one letter, one digit
– 1. Check for the digit
isdigit:=FALSE;
m := length(password);
FOR i IN 1..10 LOOP
FOR j IN 1..m LOOP
IF substr(password,j,1) = substr(digitarray,i,1) THEN
isdigit:=TRUE;
GOTO findchar;
END IF;
END LOOP;
END LOOP;
IF isdigit = FALSE THEN
raise_application_error(-20008, ‘Password must contain at least one digit, one character’);
END IF;
– 2. Check for the character
<>
ischar:=FALSE;
FOR i IN 1..length(chararray) LOOP
FOR j IN 1..m LOOP
IF substr(password,j,1) = substr(chararray,i,1) THEN
ischar:=TRUE;
GOTO endsearch;
END IF;
END LOOP;
END LOOP;
IF ischar = FALSE THEN
raise_application_error(-20009, ‘Password must contain at least one \
digit, and one character’);
END IF;
<>
– Check if the password differs from the previous password by at least
– 3 letters
IF old_password IS NOT NULL THEN
differ := length(old_password) - length(password);
differ := abs(differ);
IF differ < 3 THEN
IF length(password) < length(old_password) THEN
m := length(password);
ELSE
m := length(old_password);
END IF;
FOR i IN 1..m LOOP
IF substr(password,i,1) != substr(old_password,i,1) THEN
differ := differ + 1;
END IF;
END LOOP;
IF differ < 3 THEN
raise_application_error(-20011, ‘Password should differ from the \
old password by at least 3 characters’);
END IF;
END IF;
END IF;
– Everything is fine; return TRUE ;
RETURN(TRUE);
END;
– This script alters the default parameters for Password Management
– This means that all the users on the system have Password Management
– enabled and set to the following values unless another profile is
– created with parameter values set to different value or UNLIMITED
– is created and assigned to the user.
ALTER PROFILE DEFAULT LIMIT
IDLE_TIME 600 –10小时连续不活动的话系统自己主动断开连接
PASSWORD_LIFE_TIME 1720
PASSWORD_GRACE_TIME 7
PASSWORD_REUSE_TIME UNLIMITED
PASSWORD_REUSE_MAX UNLIMITED
FAILED_LOGIN_ATTEMPTS 10
PASSWORD_LOCK_TIME 1
PASSWORD_VERIFY_FUNCTION verify_function_11G;
select * from dba_profiles where profile = ‘DEFAULT’;
搞定
最后一个select 是check喽。
So easy。
Have U got？*