STL之accumulate()

accumulate(A,A+N,num,multiplies<int>))     //数组累乘  ,再和n相乘

accumulate(A, A + N, num);                        //数组累加  ,再和n相加

别忘了把头文件  #include<numeric>包含进来

#include<iostream>
#include<numeric>
using namespace std;
int main()
{
	int A[5] = { 2, 3, 1, 1, 10 };
	int N = 5;

	int product = accumulate(A, A+N, 10, multiplies<int>());
	cout << "product = " << product << endl;

	int sum = accumulate(A, A + N, 10);
	cout << "sum = " << sum << endl;
	
	system("pause");
	return 0;
}

运行结果:

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转载自blog.csdn.net/fadbgfnbxb/article/details/88844614