[2019-04-02] LeetCode

1. Two Sum

Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,Because nums[0] + nums[1] = 2 + 7 = 9,return [0,1].

class Solution(object):
     def twoSum(self, nums, target):
    	if len(nums) <= 1:
        	 return False
     	buff_dict = {}
     	for i in range(len(nums)):
        	 if nums[i] in buff_dict:
            	 return [buff_dict[nums[i]], i]
         	 else:
                 buff_dict[target - nums[i]] = i

猜你喜欢

转载自blog.csdn.net/weixin_43951303/article/details/88975289