CCF认证201809-2买菜

CCF认证201809-2买菜题目描述

#include<iostream>
#include<cmath>
using namespace std;
const int N=2000;
struct node{
	int start;
	int end;
};
node a[N+5];
node b[N+5];
int main()
{
	int n;
	cin>>n;
	for(int i=1;i<=n;i++)
	{
		cin>>a[i].start>>a[i].end;
	}
	for(int i=1;i<=n;i++)
	{
		cin>>b[i].start>>b[i].end;
	}
	int sum=0;
	int start1,end1,start2,end2;
	for(int i=1,j=1;i<=n&&j<=n;)
	{
		start1=a[i].start;
		end1=a[i].end;
	    start2=b[j].start;
		end2=b[j].end;
		if(start2<=end1&&start2>=start1)
		{
			sum+=min(end1-start2,end2-start2);
			//cout<<"sum1="<<sum<<endl;
			if(end2<end1)
			{
				j++;
			}
			else if(end2>end1)
			{
				i++;
			} 
			else
			{
				i++;
				j++;
			}
		}
		else if(start1<=end2&&start1>=start2)
		{
			sum+=min(end1-start1,end2-start1);
			//cout<<"sum2="<<sum<<endl;
			if(end2<end1)
			{
				j++;
			}
			else if(end2>end1)
			{
				i++;
			} 
			else
			{
				i++;
				j++;
			}
	    }
	    else if(end1<=start2)
	    {
	    	i++;
		}
		else if(end2<=start1)
		{
			j++;
		}		
  }
  cout<<sum<<endl;
	return 0;
}

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转载自blog.csdn.net/amf12345/article/details/89061425