今天刚刚学习的python

1,同一用户名的秘密输入错误3次后将被锁定
2.用户名和密码都正确时,显示登陆成功


#!/usr/bin/env python
#-*-coding=utf-8 -*-
#AUTHOR:duwentao

username = ['yuzo','hy'] #存储用户名
password = ['123123','454545'] #存储对应的密码
locking = [] #用于锁定
n = 0 #计算输入了几次
while True:
UserName = input('name:')
if UserName not in locking:
if UserName in username:
PassWord = input('password:')
if PassWord == password[username.index(UserName)]:
print ('登录成功')
exit()
else:
n = n+1
if n == 3:
locking.append(UserName)
print ('用户名或者密码错误,登录失败')
else:
PassWord = input('password:')
print ("用户名或者密码错误,登录失败")
else:
print ("该用户已被锁定")

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转载自www.cnblogs.com/clock271659148/p/10667394.html