我的算法之路8--环形链表

# Definition for singly-linked list.
# class ListNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution(object):
    def hasCycle(self, head):
        """
        :type head: ListNode
        :rtype: bool
        """
        if not head or not head.next:
            return False
        fast=head
        slow=head
        while(fast.next and fast.next.next):
            fast=fast.next.next
            slow=slow.next
            if slow.val==fast.val:
                return True
        return False

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转载自blog.csdn.net/joaming/article/details/89359704