js笔试题—在数组找到和为一个数的两个数,每个数只能用一次

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<script type="text/javascript">
		function sum(arr,num){
			arr = unique(arr);
			var rel = [];
			arr.sort();
			var low = 0,heigh = arr.length - 1;
			while(low <= heigh){
				for (var i = 0; i < arr.length; i++) {
					if(arr[low] + arr[heigh] < num){
						low++; 
					}else if(arr[low] + arr[heigh] > num){
						heigh --;
					}else{
						rel.push(arr[low]);
						rel.push(arr[heigh]);
						return rel;
					}
				 }
			}
		}

		//数组去重
		function unique(arr){
			var target = {};
			var newArr = [];
			var len = arr.length;
			for(var i = 0;i < len; i++){
				if(!target[arr[i]]){
					newArr.push(arr[i]);
					target[arr[i]] = 'a';
				}
			}
			return newArr;
		}

		var arr = [1,2,4,2,8,6,6,5,3];
		var newa = sum(arr,8);
		console.log(newa);


	</script>

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转载自blog.csdn.net/qq_39396275/article/details/82759185