数据库SQL实战 --26.查找描述信息中包括robot的电影对应的分类名称以及电影数目,而且还需要该分类对应电影数量大于5部

题目描述

查找描述信息中包括robot的电影对应的分类名称以及电影数目,而且还需要该分类对应电影数量>=5部
CREATE TABLE IF NOT EXISTS film (
film_id smallint(5)  NOT NULL DEFAULT '0',
title varchar(255) NOT NULL,
description text,
PRIMARY KEY (film_id));

CREATE TABLE category  (
category_id  tinyint(3)  NOT NULL ,
name  varchar(25) NOT NULL, `last_update` timestamp,
PRIMARY KEY ( category_id ));

CREATE TABLE film_category  (
film_id  smallint(5)  NOT NULL,
category_id  tinyint(3)  NOT NULL, `last_update` timestamp);

解决思路

SELECT c.name, COUNT(fc.film_id) FROM
 (select category_id, COUNT(film_id) AS category_num FROM
     film_category  GROUP BY category_id HAVING count(film_id)>=5) AS cc,
 film AS f, film_category AS fc, category AS c
WHERE  f.description LIKE '%robot%'
AND f.film_id = fc.film_id
AND c.category_id = fc.category_id
AND c.category_id=cc.category_id
  • 找到对应电影数量>=5的所有分类,建立成虚表cc:
    (select category_id, count(film_id) as category_num from film_category group by category_id having count(film_id)>=5) as cc
  • 设定限制条件 f.description like ‘%robot%’
  • 在表cc、f、fc、c中查找包括robot的电影对应的分类名称和对应的电影数目。

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转载自blog.csdn.net/ouzhuangzhuang/article/details/89672935