题目连接https://www.luogu.org/problemnew/show/P1378
解题思路:利用深度优先搜索,暴力枚举即可,反正最多只有两个点,最大也就搜索6!次
#include<bits/stdc++.h>
using namespace std;
int vis[10],n;
double r[10],x[10],y[10],p;
double xl,yl,x2,y2,s;
const double pi=acos(-1);
double cal(int i)
{
double s1=min(fabs(x[i]-xl),fabs(x[i]-x2));
double s2=min(fabs(y[i]-yl),fabs(y[i]-y2));
double ans=min(s1,s2);
for(int j=0;j<n;j++)
{
if(!vis[j]) continue;
double d=sqrt((x[i]-x[j])*(x[i]-x[j])+(y[i]-y[j])*(y[i]-y[j]));
ans=min(ans,max(d-r[j],0.0));
}
return ans;
}
void dfs(int k,double sum)
{
if(k==n)
{
p=max(p,sum);
return ;
}
for(int i=0;i<n;i++)
{
if(!vis[i])
{
r[i]=cal(i);
vis[i]=1;
dfs(k+1,sum+r[i]*r[i]*pi);
vis[i]=0;
}
}
}
int main()
{
//freopen("t.txt","r",stdin);
scanf("%d",&n);
scanf("%lf%lf%lf%lf",&xl,&yl,&x2,&y2);
//cout<<xl<<" "<<yl<<endl;
memset(vis,0,sizeof(vis));
for(int i=0;i<n;i++)
{
scanf("%lf%lf",&x[i],&y[i]);
}
p=0;
dfs(0,0);
s=fabs(xl-x2)*fabs(yl-y2);
printf("%d",(int)(s-p+0.5));
return 0;
}