【JAVA基础】-- List

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java8

1.按顺序排列

List<Entity> list = new ArrayList();
//按时间顺序
list.stream().sorted(Comparator.comparing(Entity::getCreateTime)).collect(Collectors.toList());
//按时间逆序
list.stream().sorted(Comparator.comparing(Entity::getCreateTime).reversed()).collect(Collectors.toList());
//按id从小到大
List<User> sortUser = list.stream().sorted((u1, u2) -> u1.getId().compareTo(u2.getId())).collect(Collectors.toList());
////按id从大到小
List<User> sortUser = list.stream().sorted((u1, u2) -> u2.getId().compareTo(u1.getId())).collect(Collectors.toList());
List<Integer> integerList = Arrays.asList(4, 5, 2, 3, 7, 9);
List<Integer> collect = integerList.stream()
        .map(i -> i * i).distinct()
        .collect(Collectors.toList());
Collections.sort(collect);  //升序
//collect.sort(Comparator.reverseOrder()); //倒序
collect.forEach(System.out::println);
// 如果两个苹果的重量一样重,怎么办?那就再找一个条件进行排序呗
inventory.sort(comparing(Apple::getWeight).reversed().thenComparing(Apple::getColor))

2.list分组去重

分组:

classEntities.stream().collect(Collectors.groupingBy(ClassEntity::getGrade));

去重(根据年级和专业,当年级和专业都相同的情况下看做是重复数据):

List<ClassEntity> distinctClass = classEntities.stream().collect(Collectors.collectingAndThen(Collectors.toCollection(() -> new TreeSet<>(Comparator.comparing(o -> o.getProfessionId() + ";" + o.getGrade()))), ArrayList::new));


通过hashSet去重(如将classNames去重):该种去重是bean完全相同的时候算重复数据

List<String> classNameList = new ArrayList(new HashSet(classNames));

补:java8 快速实现List转map 、分组、过滤等操作

       java找出2个集合相同和不同的元素(以及去除List中的重复元素)

 

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转载自blog.csdn.net/qqxyy99/article/details/86612343