列表中的字典根据 下标为零的去重
l1 = [['b', 1], ['b', 2], ['c', 3], ['a', 1], ['b', 1], ['b', 1], ] l2 = [] l2.append(l1[0]) for data in l1[1:]: k = 0 for item in l2: if data[0] != item[0]: k = k + 1 else: break if k == len(l2): l2.append(data) print(l2)
将下表为1的数值相加操作
z = {} for i in l1: z.setdefault(i[0],[]).append(i[1]) d = [[i,sum(z[i])] for i in z] print(d) # print([[i,sum(z[i])] for i in z])
z={} for i in l1: if i[0] not in z.keys(): z[i[0]] = i else: z[i[0]][1] += i[1] print(z.values())