Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as 1
and 0
respectively in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[ [0,0,0], [0,1,0], [0,0,0] ]
The total number of unique paths is 2
.
public class Solution {
public int uniquePathsWithObstacles(int[][] obstacleGrid) {
int m = obstacleGrid.length;
int n = obstacleGrid[0].length;
int[][] res = new int[m][n];
for(int i = 0; i < m; i++)
for(int j = 0; j < n; j++)
res[i][j] = 0;
for(int i = 0; i < m; i++){
if (obstacleGrid[i][0] == 1)
break;
res[i][0] = 1;
}
for(int i = 0; i < n; i++){
if (obstacleGrid[0][i] == 1)
break;
res[0][i] = 1;
}
for(int i = 1; i < m; i++){
for(int j = 1; j < n; j++){
if (obstacleGrid[i][j] != 1)
res[i][j] = res[i][j-1] + res[i-1][j];
}
}
return res[m-1][n-1];
}
}
是之前那篇的变种,加了一个判断就好。