JavaScript中一个对象数组按照另一个数组排序
需求:排序
const arr1 = [33, 11, 55, 22, 66];
const arr2 = [{age: 55}, {age: 22}, {age: 11}, {age: 66}, {age: 33}]
- 数组arr2中每项都是一个对象,对象中age属性 === 数组arr1中的项
- 将arr2数组根据对象的age值在arr1中的位置排序, 排序后的结果为 `const arr2 = [ {age: 33},{age: 11}, {age: 55}, {age: 22}, {age: 66}]
步骤:
const arr1 = [33, 11, 55, 22, 66];
const arr2 = [{age: 55}, {age: 22}, {age: 11}, {age: 66}, {age: 33}]
console.log('排序前arr2 => ', arr2)
// 排序 arr2
arr2.sort((prev, next) => {
const p = arr1.indexOf(prev.age)
const n = arr1.indexOf(next.age)
return p - n
})
// 排序 arr2(简写)
arr2.sort((prev, next) => {
return arr1.indexOf(prev.age) - arr1.indexOf(next.age)
})
console.log('排序后arr2 => ', arr2)
console.log(' arr1 => ', arr1)