SDNU 1245.这题超难的,建议先做其他的,看都不要看(思维)

Description

求组合数C(n,m)

Input

T(0 < T < 2000)
每组样例两个数n, m(0 < n, m< 60)
 

Output

C(n,m)

Sample Input

2
1 1
2 1

Sample Output

1
2

Source

Unknown
思路:真是一道神奇的题啊,我想着用常规的办法去求解,但是爆了long long也不自知,真是傻。然后用了优化。
#include <cstdio>
#include <iostream>
#include <cmath>
#include <string>
#include <cstring>
#include <algorithm>
#include <queue>
#include <vector>
#include <map>
using namespace std;
#define ll long long

int t, n, m;
ll sum1;

int main()
{
    scanf("%d", &t);
    while(t--)
    {
        sum1 = 1;
        scanf("%d%d", &n, &m);
        for(int i = 1; i <= m; i++)
        {
            sum1 *= (n-i+1);
            sum1 /= i;
        }
        printf("%lld\n", sum1);
    }
    return 0;
}

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转载自www.cnblogs.com/RootVount/p/10991748.html