Python3-正则表达式~pattern.findall

import re

pattern=re.compile(r'\d+')
# pattern=re.compile(r'\d')#['1', '2', '3', '4', '5', '6', '7', '8', '9']
s=pattern.findall('hello 12345 6789')
# print(s)#['12345', '6789']

# 举例1：I love China 输出：anihC evol I
str='I love China!'

#方法一
# def reverse_out(str):
#     i=len(str)-1
#     while i>=0:
#         print(str[i])
#         i-=1

#方法二 正则
# pattern=re.compile(r'.')
# s=pattern.findall(str)
# print(s)#['I', ' ', 'l', 'o', 'v', 'e', ' ', 'C', 'h', 'i', 'n', 'a', '!']


#例二 I love China 输出：I evol anihC
# pattern=re.compile(r'\w+!?')#['I', 'love', 'China']
# pattern=re.compile(r'.+')#['I love China']
# pattern=re.compile(r'(\w+)(!?)')#[('I', ''), ('love', ''), ('China', '!')]
# s=pattern.findall(str)
# print(s)

# for item in s:
#     reverse_out(item)


#匹配小数
pattern = re.compile(r'\d+\.\d*')
s = pattern.findall("3.241592653 PI 100 10001.11 3.")
print(s)

['3.241592653', '10001.11', '3.']


Process finished with exit code 0