Leetcode队列及递归初步

27. Remove Element
Given an array nums and a value val, remove all instances of that value in-place and return the new length.

Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.

The order of elements can be changed. It doesn’t matter what you leave beyond the new length.

Example 1:

Given nums = [3,2,2,3], val = 3,

Your function should return length = 2, with the first two elements of nums being 2.

It doesn’t matter what you leave beyond the returned length.
JAVA

class Solution {
    public int removeElement(int[] nums, int val) {
         int j=0;
        for(int i=0;i<nums.length;i++)
        {
            if(nums[i]!=val)
            {
                nums[j]=nums[i];
                j++;
            }
        }
    
        return j;
    }
    }

C++

class Solution {
public:
    int removeElement(vector<int>& nums, int val) {
        int j=0;
        for(int i=0;i<nums.size();i++)
        {
            if(nums[i]!=val)
            {
                nums[j]=nums[i];
                j++;
            }
        }
    
        return j;
    }
};

225. Implement Stack using Queues

Implement the following operations of a stack using queues.

push(x) – Push element x onto stack.
pop() – Removes the element on top of the stack.
top() – Get the top element.
empty() – Return whether the stack is empty.
Example:

MyStack stack = new MyStack();

stack.push(1);
stack.push(2);
stack.top(); // returns 2
stack.pop(); // returns 2
stack.empty(); // returns false
用队列来实现栈
C++

class MyStack {
public:
    /** Initialize your data structure here. */
    MyStack() {
            
    }
    
    /** Push element x onto stack. */
    void push(int x) {
     q.push(x);
     for(int i=0;i<(int)q.size()-1;i++)
      {
         q.push(q.front());
         q.pop();     
        }
        
    }
    
    /** Removes the element on top of the stack and returns that element. */
    int pop() {
      int x = q.front(); q.pop();
        return x;
        
    }
    
    /** Get the top element. */
    int top() {
        return q.front();
    }
    
    /** Returns whether the stack is empty. */
    bool empty() {
        return q.empty();
    }
private:
    queue<int> q;
};

/**
 * Your MyStack object will be instantiated and called as such:
 * MyStack* obj = new MyStack();
 * obj->push(x);
 * int param_2 = obj->pop();
 * int param_3 = obj->top();
 * bool param_4 = obj->empty();
 */

933. Number of Recent Calls
Write a class RecentCounter to count recent requests.

It has only one method: ping(int t), where t represents some time in milliseconds.

Return the number of pings that have been made from 3000 milliseconds ago until now.

Any ping with time in [t - 3000, t] will count, including the current ping.

It is guaranteed that every call to ping uses a strictly larger value of t than before.

Example 1:

Input: inputs = [“RecentCounter”,“ping”,“ping”,“ping”,“ping”], inputs = [[],[1],[100],[3001],[3002]]
Output: [null,1,2,3,3]
写一个RecentCounter类来计算最近的请求。
看不懂(为了应付考试)
JAVA

class RecentCounter {
TreeSet<Integer> ts;
    public RecentCounter() {
         ts=new TreeSet<>();
    }
    
    public int ping(int t) {
        ts.add(t);
        return ts.tailSet(t-3000).size();
    }
}

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转载自blog.csdn.net/qq_37617419/article/details/93144454