1 // 2 // main.c 3 // 统计输入单词数 4 // 5 // Created by LongMa on 2019/6/27. 6 // Copyright © 2019 . All rights reserved. 7 // 8 9 #include <stdio.h> 10 #include <string.h> 11 12 int main(int argc, const char * argv[]) { 13 14 //输入一个英文句子，英文句以空格分隔。统计句子中有多少个单词。 15 //eg:how are you,有3个单词 16 char string[80]; 17 printf("请输入英文句子："); 18 gets(string); 19 20 char c; 21 char kongGe[2] = " "; 22 int word = 0; 23 int num = 0; 24 25 for (int i = 0; (c = string[i]) != '\0'; i++) { 26 if (c == 32) {//当前位为空格（ASCII码值为32）时，word记录为0.注意：xcode中strcmp(&c, " ")为-120，不为0,strcmp比较的是字符串，不能比较字符和字符串！ 27 printf("%d,%d是否相等：%d\n",c,kongGe[0], strcmp(&kongGe[0], &c)); 28 word = 0; 29 }else{//当前位不为空格时 30 if(0 == word){//上一位为空格/第一位是字母时 31 num += 1; 32 word = 1; 33 }else{//上一位不为空格时，不能算一个单词 34 //do nothing 35 } 36 } 37 } 38 39 printf("语句：%s\n", string); 40 printf("单词数:%d个",num); 41 return 0; 42 }
log：
请输入英文句子：warning: this program uses gets(), which is unsafe. how are you 32,32是否相等：-120 32,32是否相等：-120 语句：how are you 单词数:3个Program ended with exit code: 0