获取字符串最长不重复子串

# coding:utf-8
def find_longest_no_repeat_substr(one_str):
    '''''
    找出来一个字符串中最长不重复子串
    '''
    res_list = []
    length = len(one_str)
    for i in range(length):#分别以字符串的每个字符作为自串的第一个字符
        tmp = one_str[i]#记录不重复自串的中间变量
        for j in range(i + 1, length):
            if one_str[j] not in tmp:
                tmp += one_str[j]
            else:
                break
        res_list.append(tmp) #保存所有的不重复子串
    res_list.sort(lambda x, y: cmp(len(x), len(y)),reverse = True)#根据每个不重复子串长度降序排列
    return res_list[0]


if __name__ == '__main__':
    one_str_list = ['120135435', 'abdfkjkgdok', '123456780423349']
    for one_str in one_str_list:
        res = find_longest_no_repeat_substr(one_str)
        print   '{0}最长非重复子串为:{1}'.format(one_str, res)

  

猜你喜欢

转载自www.cnblogs.com/alasijia/p/11242035.html