python 判断一个字符串组合后,是否在另一个字符串中

code

#coding=utf-8

def getdic(s):
    dic = {}
    for i in s:
        if (i not in dic):
            dic[i] = 1
        else:
            dic[i] += 1
    return dic

s1="csddc"
s2="cdcsdsdwegtghyhjk"

dics1=getdic(s1)

length=len(s1)
flag=False

for i in range(len(s2)):
    if(s2[i] in s1):
        if(getdic(s2[i:i+length])==dics1):
            flag=True
            break

if(flag):
    print("Founded!")
else:
    print("No founded!")

输出

Founded!

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转载自www.cnblogs.com/sea-stream/p/11285336.html