AcWing 5. 多重背包问题 II

//二进制优化    最后变为01背包 
#include <iostream>
#include <algorithm>
using namespace std;
const int N = 12010, M = 2010;
int n, m;
int v[N], w[N];
int f[M];
int main() {
    cin >> n >> m;
    int cnt = 0;
    for (int i = 1; i <= n; i ++ ) {
        int a, b, s;
        cin >> a >> b >> s;
        int k = 1;
        while (k <= s) {
            cnt ++ ;
            v[cnt] = a * k;
            w[cnt] = b * k;
            s -= k;
            k *= 2;
        }
        if (s > 0) {
            cnt ++ ;
            v[cnt] = a * s;
            w[cnt] = b * s;
        }
    }
    n = cnt;
    for (int i = 1; i <= n; i ++ )
        for (int j = m; j >= v[i]; j -- )
            f[j] = max(f[j], f[j - v[i]] + w[i]);
    cout << f[m] << endl;
    return 0;
}