POJ 1035 Spell checker(哈希表)

/*
题意:输入字典,然后输入单词,判断字典中是否出现过该单词,或者是否进行删除、添加、替换操作,如果是,则输出对应的字典中的单词
要求按照输入时候的排名输出

题解:建立两个哈希表。一个存储字典和输入字典中单词的排名,一个进行最后输出的判重
*/

#include <iostream>
//#define 
using namespace std;
const int HASH = 12007;
char list1[HASH][18];
int rank[HASH];
int head1[HASH];

char list2[HASH][18];
int head2[HASH];

int ans[10007];
int ansLen;

char word[57];
char tempWord[57];


int insert1(char *s, int pos)
{
	int len = strlen(s);
	int i, k = 0;
	for(i = 0; i < len; ++ i)
		k = (k * 26 + s[i] - 'a') % HASH;
	while(head1[k] != 0 && strcmp(list1[k], s) != 0)
	{
		k = (k + 1) % HASH;
	}
	if(!head1[k])
	{
		head1[k] = 1;
		strcpy(list1[k], s);
		rank[k] = pos;
		return 1;
	}
	return 0;
}

int insert2(char *s)
{
	int len = strlen(s);
	int i, k = 0;
	for(i = 0; i < len; ++ i)
		k = (k * 26 + s[i] - 'a') % HASH;
	while(head2[k] != 0 && strcmp(list2[k], s) != 0)
	{
		k = (k + 1) % HASH;
	}
	if(!head2[k])
	{
		head2[k] = 1;
		strcpy(list2[k], s);
		return 1;
	}
	return 0;
}

int exist(char *s)
{
	int len = strlen(s);
	int i, k = 0;
	for(i = 0; i < len; ++ i)
		k = (k * 26 + s[i] - 'a') % HASH;
	while(head1[k] != 0 && strcmp(list1[k], s) != 0)
	{
		k = (k + 1) % HASH;
	}
	if(!head1[k])
	{
		return -1;
	}
	return k;
}

int cmp(const void *a, const void *b)
{
	int *pa = (int *) a;
	int *pb = (int *) b;
	return rank[*pa] - rank[*pb];
}

int main()
{
	//int flag = 0;
	//freopen("e://data.in", "r", stdin);
	while(gets(word))
	{
		memset(head1, 0, sizeof(head1));
		
		int pos = 0;
		while(word[0] != '#')
		{
			insert1(word, pos ++);
			gets(word);
		}
		gets(word);
		while(word[0] != '#')
		{
			memset(head2, 0, sizeof(head2));
			ansLen = 0;
			printf("%s", word);
			if(exist(word) > -1)
			{
				printf(" is correct\n");
				gets(word);
				continue;
			}
			int len = strlen(word);
			int i, k;
			char j;
			int z;
			for(i = 0; i <= len; ++ i)
			{
				strcpy(tempWord, word);
				for(k = len; k >= i; k --)
					tempWord[k + 1] = tempWord[k];
				for(j = 'a'; j <= 'z'; ++ j)
				{
					tempWord[i] = j;
					if((z = exist(tempWord)) > -1 && insert2(tempWord))
					{
						ans[ansLen ++] = z;
					}
				}
			}
			for(i = 0; i < len; ++ i)
			{
				strcpy(tempWord, word);
				for(k = i + 1; k <= len; ++ k)
					tempWord[k - 1] = tempWord[k];
				if((z = exist(tempWord)) > -1 && insert2(tempWord))
				{
					ans[ansLen ++] = z;
				}
			}
			for(i = 0; i < len; ++ i)
			{
				strcpy(tempWord, word);
				for(j = 'a'; j <= 'z'; ++ j)
				{
					tempWord[i] = j;
#ifdef TEST
					if(j == 'd')
					{
					printf("\n");
					}
#endif
					if((z = exist(tempWord)) > -1 && insert2(tempWord))
					{
						ans[ansLen ++] = z;
					}
				}
			}
			qsort(ans, ansLen, sizeof(ans[0]), cmp);
			printf(":");
			for(i = 0; i < ansLen; ++ i)
				printf(" %s", list1[ans[i]]);
			printf("\n");
			gets(word);
		}
	}
	return 0;
}

更多详细信息请查看 java教程网 http://www.itchm.com/forum-59-1.html

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转载自aijuans.iteye.com/blog/1636539
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