pgsql SQL复杂查询示例

 


WITH tmp AS(
SELECT sum(sessioncount) as visitCount, appid from t_stat_visit where stattype = '1' GROUP BY appid
)
SELECT
t1.*, t2.visitCount
FROM
t_e_oauth_application t1 LEFT JOIN tmp t2 on t1.appid = t2.appid
WHERE
EXISTS (
SELECT
ID
FROM
t_e_app_version
WHERE
t1. ID = t_e_app_version.appid
AND t_e_app_version.status = '6'
)
AND t1.createorid = #{creatorId}
ORDER BY lastmodifytime DESC

 

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转载自www.cnblogs.com/scode2/p/9044201.html